PHP加载json数据，输出为空

Question

我尝试从我的JSON文件加载数据到php，但我的oupt是emtpy什么是错误？

JSON：

{ 
    "drinks":[ 

    "1" {"coffee": "zwart", "country":"afrika"}, 

    "2" {"tea": "thee", "country":"china"}, 

    "3" {"water": "water", "country":"netherlands"}, 
    ] 
} 

PHP：

<?php 
$str = file_get_contents('data.json'); 
$json = json_decode($str, true); 
$drinks = $json['drinks'][0][coffee]; 

echo $drinks; 
?> 

Answer 1

你的JSON输入无效根据RFC 4627（JSON specification）。所以，正确的JSON字符串必须是：

{"drinks":[ 
       {"coffee": "zwart", "country":"afrika"}, 
       {"tea": "thee", "country":"china"}, 
       {"water": "water", "country":"netherlands"} 
      ] 
    } 

因此您的代码将工作：

$str = file_get_contents('data.json'); 
$json = json_decode($str, true);  
$drinks = $json['drinks'][0]['coffee']; 
echo $drinks; 

或者至少，你必须格式化你的JSON字符串象下面这样：

{ 
    "drinks":[  
     { 
     "1": {"coffee": "zwart", "country":"afrika"},  
     "2": {"tea": "thee", "country":"china"},  
     "3": {"water": "water", "country":"netherlands"} 
     } 
    ] 
} 

你可以通过这种方式获取数据：

$str = file_get_contents('data.json'); 
$json = json_decode($str, true); 
$drinks = $json['drinks'][0]['1']['coffee']; 
echo $drinks;