在bash中搜索并回显字符串的一部分

在一个字符串中搜索给定模式并在不使用awk的情况下回应它的最佳方式（在bash中）是什么？我想要使用标准命令，如grep,cat,cut或sed。在bash中搜索并回显字符串的一部分

实施例：

我想从lspci命令的输出去掉所有的USB控制器的设备地址：

[[email protected] ~]$ lspci 

00:00.0 Host bridge: Intel Corporation Core Processor DRAM Controller (rev 18) 
00:1a.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05) 
00:1c.0 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 1 (rev 05) 
00:1c.4 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 5 (rev 05) 
00:1c.5 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 6 (rev 05) 
00:1d.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05) 
00:1e.0 PCI bridge: Intel Corporation 82801 PCI Bridge (rev a5) 
00:1f.0 ISA bridge: Intel Corporation 3400 Series Chipset LPC Interface Controller (rev 05) 
00:1f.2 RAID bus controller: Intel Corporation 82801 SATA Controller [RAID mode] (rev 05) 
00:1f.3 SMBus: Intel Corporation 5 Series/3400 Series Chipset SMBus Controller (rev 05) 
02:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection 
03:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection 
04:03.0 VGA compatible controller: Matrox Graphics, Inc. MGA G200eW WPCM450 (rev 0a)

我想检索（打印出）的两串：

00:1a.0 
00:1d.0

来源

2012-10-25 Gianluca Ghettini

我想知道谁会想出更多的可能性。

lspci | grep 'USB Controller' | sed "s/ .*//" 
lspci | grep 'USB Controller' | grep -o '^[^ ]*' 
lspci | grep 'USB Controller' | while read id rest ; do echo $id ; done 
lspci | grep 'USB Controller' | cut -f 1 -d ' '

来源

2012-10-25 08:08:17 January

非常干净！谢谢你 –

sed -n '/USB controller/{s/ .*//;p}'

来源

2012-10-25 08:09:35 Guru

lspci | grep 'USB Controller' | cut -d' ' -f1

来源

2012-10-25 08:10:19 miono

在bash中搜索并回显字符串的一部分

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