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我正在尝试在我的模式中创建一个分页继电器& graphql。这是我的代码:如何在relay和graphql模式中正确创建连接?
const GraphQLFriendByUser = new GraphQLObjectType({
name: 'FriendByUser',
fields: {
id: globalIdField('FriendByUser'),
_id: {
type: GraphQLString,
resolve: (root) => root._id,
},
email: {
type: GraphQLBoolean,
resolve: (root) => root.email,
},
fullName: {
type: GraphQLString,
resolve: (root) => {
return root.fullName;
},
},
},
interfaces: [nodeInterface],
});
const {
connectionType: FriendsByUserConnection,
edgeType: GraphQLFriendByUserEdge,
} = connectionDefinitions({
name: 'FriendByUser',
nodeType: GraphQLFriendByUser,
});
我创造了这个在待办事项现代同样在看样品,在我TodoListHome组件,这是我graphql查询:
friendsByUserContext(first: 200) @connection(key: "TodoListHome_friendsByUserContext") {
id
_id
fullName
email
}
有当我更新的模式没有问题,但是当我尝试建立,这是我的错误:
Invariant Violation: RelayParser: Unknown field
id
on typeFriendByUserConnection
. Source: documentTodoListHome_viewer
file:C:\Users\PE60\Desktop\socialnetworking-todoapp\js\components\TodoListHome.js
.
执行甚至没有达成解决,所以我无法登录。但我相信错误不在那里。帮帮我?