我想要的东西很简单,但似乎没有工作。我想创建一个名为db_conn()的函数,所以我可以调用它来打开一个mysql数据库,而不是每次需要时都进行新的调用。下面是函数:数据库连接功能
/**************************************
Open Database Connection Function.
***************************************/
/* Database Connection Settings */
$_SESSION['servername'] = "localhost";
$_SESSION['mysql_username'] = "abc123";
$_SESSION['mysql_password'] = "mypass";
$_SESSION['dbname'] = "dbname";
function db_conn() {
$conn = new mysqli($_SESSION['servername'], $_SESSION['mysql_username'], $_SESSION['mysql_password'], $_SESSION['dbname']);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
// Test if connection succeeded
if(mysqli_connect_errno()) {
die("Database connection failed: " .
mysqli_connect_error() .
" (" . mysqli_connect_errno() . ")"
);
}
}
示例调用的功能和回声出数据:
<?php
db_conn();
$sql = "SELECT id, region FROM tbl_region;";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo '<td width="1"><label for="delete">
<input type="radio" name="region" id="region" value="'.$row["id"].'">
</label></td>';
echo '<td align="left" valign="top"><p>'.$row["region"].'</p></td></tr>';
}
}
?>
当我测试它停止在上面的代码,并且不显示任何错误的页面。有人可以告诉我我在做什么错误的db_conn函数?
是什么在的phpinfo使用error_reporting节目吗? –