Python在网格中放置1的“b”

Question

我有一个看起来像这样的网格。我在网格中随机放置一个“b”，并把数字1围绕字母“b”。这似乎在任何地方都可以工作，除非1应该放在最下面一行和一列到最右边。例如，它会是这个样子

0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 1 0 
0 0 0 0 0 0 0 0 1 b 
0 0 0 0 0 0 0 0 0 0 

，它应该看起来像

0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 1 1 
0 0 0 0 0 0 0 0 1 b 
0 0 0 0 0 0 0 0 1 1 

这里是我使用的代码，我想不通为什么这些1的的arent被放置在那里。

from random import* 
mat1 = [] 
mat2 = [] 

def makemat(x): 
    for y in range(x): 
     list1 = [] 
     list2 = [] 
     for z in range(x): 
      list1.append(0) 
      list2.append("-") 
     mat1.append(list1) 
     mat2.append(list2) 
makemat(10) 


def printmat(mat): 
    for a in range(len(mat)): 
     for b in range(len(mat)): 
      print(str(mat[a][b]) + "\t",end="") 
     print("\t") 



def addmines(z): 
    count = 0 
    while (count < z): 
     x = randrange(0,len(mat1))  
     y = randrange(0,len(mat1))  
     if mat1[y][x] == "b": 
      count -= 1 
     else: 
      mat1[y][x] = "b" 
     count += 1 
addmines(1) 




def addscores(): 
    for x in range(len(mat1)): 
     for y in range(len(mat1)): 
      if ((y < len(mat1)-1) and (x < len(mat1)-1)) and ((y >= 0) and (x >= 0))): 
       if mat1[y+1][x] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x] == "b": 
        mat1[y][x] = 1 
       if mat1[y][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y][x-1] == "b": 
        mat1[y][x] = 1 
       if mat1[y+1][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y+1][x-1] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x-1] == "b": 
        mat1[y][x] = 1 
    printmat(mat1) 
addscores() 

Answer 1

您的嵌套循环检查每个方块，看看它是否应该有一个1。但是，在addscores()的第一个if子句中，您忽略了位于正方形边缘上的每个正方形。解决这个问题的好方法是省略if cluase，而是添加一个函数来检查一个自动检查边界的正方形。例如：

def checksqu(y, x): 
    if y < 0 or y >= len(mat1) or x < 0 or x >= len(mat1): 
     return False 
    return mat1[y][x] == 'b' 

然后，而不是if mat1[y - 1][x - 1]:，你可以做if checksqu(y - 1, x - 1):（和等等）。

Answer 2

可以简化这一部分：

def addscores(): 
    for x in range(len(mat1)): 
     for y in range(len(mat1)): 
      if ((y < len(mat1)-1) and (x < len(mat1)-1)) and ((y >= 0) and (x >= 0))): 
       if mat1[y+1][x] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x] == "b": 
        mat1[y][x] = 1 
       if mat1[y][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y][x-1] == "b": 
        mat1[y][x] = 1 
       if mat1[y+1][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y+1][x-1] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x+1] == "b": 
        mat1[y][x] = 1 
       if mat1[y-1][x-1] == "b": 
        mat1[y][x] = 1 

通过使用此代码：

def addscores(): 
    size = len(mat1) 
    directions = [(dx, dy) for dx in [-1,0,1] for dy in [-1,0,1] if (dy!=0 or dx!=0)] 
    for x in range(size): 
     for y in range(size): 
      for dx, dy in directions: 
       try: 
        if mat1[y+dy][x+dx] == "b": 
         mat1[y][x] = 1 
       except: 
        pass 

Answer 3

这似乎这样的伎俩：

def addscores(mat): 
    for y in range(len(mat)): 
     for x in range(len(mat[y])): 
      if mat[y][x] == 'b': 
       mat = pad(mat, x, y, '1') 
    return mat 

def pad(mat, x, y, n): 
    for i, (x,y) in enumerate(itertools.product(range(x-1, x+2), range(y-1, y+2))): 
     if i != 4: # the coordinate at index 4 is where the bomb is 
      if 0<=y<len(mat) and 0<=x<len(mat[y]): 
       mat[y][x] = n 
    return mat 

---

测试：

In [127]: mat 
Out[127]: 
[['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '1', '1', '1'], 
['0', '0', '0', '0', '0', '0', '0', '1', '0', '1']] 

In [129]: addscores(mat) 
Out[129]: 
[['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0'], 
['0', '0', '0', '0', '0', '0', '0', '0', '1', '1'], 
['0', '0', '0', '0', '0', '0', '0', '0', '1', 'b'], 
['0', '0', '0', '0', '0', '0', '0', '0', '1', '1']]