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销售数据包含可以包含任何字符的动态产品名称。基于样本创建从 Crosstab with a large or undefined number of categories如何保留动态数据透视表上的列名
动态透视表翻译()被用于去除坏字符。
结果数据透视表列名已损坏:缺少字符和空格被删除。 如何使用与源数据中相同的列名返回数据? 我试图用
quote_ident(productname) as tootjakood,
代替
'C'||upper(Translate(productname,'Ø. &/+-,%','O')) as tootjakood,
但
错误,将返回错误:列 “Ø,12.3 /3毫米” 不存在
测试用例:
create temp table sales (saledate date, productname char(20), quantity int);
insert into sales values ('2016-1-1', 'Ø 12.3/3mm', 2);
insert into sales values ('2016-1-1', '+-3,4%/3mm', 52);
insert into sales values ('2016-1-3', '/3,2m-', 246);
do $do$
declare
voter_list text;
begin
create temp table myyk on commit drop as
select saledate as kuupaev,
'C'||upper(Translate(productname,'Ø. &/+-,%','O')) as tootjakood,
sum(quantity)::int as kogus
from sales
group by 1,2
;
drop table if exists pivot;
voter_list := (
select string_agg(distinct tootjakood, ' ' order by tootjakood) from myyk
);
execute(format('
create table pivot (
kuupaev date,
%1$s
)', (replace(voter_list, ' ', ' integer, ') || ' integer')
));
execute (format($f$
insert into pivot
select
kuupaev,
%2$s
from crosstab($ct$
select
kuupaev,tootjakood,kogus
from myyk
order by 1
$ct$,$ct$
select distinct tootjakood
from myyk
order by 1
$ct$
) as (
kuupaev date,
%4$s
);$f$,
replace(voter_list, ' ', ' + '),
replace(voter_list, ' ', ', '),
'',
replace(voter_list, ' ', ' integer, ') || ' integer' -- 4.
));
end; $do$;
select * from pivot;
使用Postgres 9.1。
非常感谢你。有相关的问题在http://stackoverflow.com/questions/35266931/returning-empty-data-from-dynamic-pivot-is-there-is-no-data – Andrus