我有几个Gmail邮箱地址，我的表的MySQL从电子邮件中删除点地址
[email protected]
[email protected]
[email protected]
[email protected]
我需要更换地址的Gmail包含符号“” 获得：
[email protected]
[email protected]
[email protected]
[email protected]
我的查询不起作用
UPDATE voters set email
replace(substring(email, 1, LOCATE('@', email) -1), '.', '')
WHERE email REGEXP '@googlemail.com|@gmail.com'
请大家帮忙，THX！
的@之前你提取子和更换点，但你的@后正在不添加回子你在这之后：
UPDATE voters
SET email = CONCAT(replace(substring(email, 1, LOCATE('@', email) -1), '.', ''),
SUBSTRING(email, LOCATE('@', email)))
WHERE email REGEXP '@googlemail.com|@gmail.com'
您可以使用使用如下面的查询类似的东西substring_index & substring：
UPDATE table1
SET email = CONCAT (
replace(substring_index(email, '@', 1), '.', '')
,substring(email, instr(email, '@'))
)
WHERE substring_index(email, '@', -1) IN (
'googlemail.com'
,'gmail.com'
);