-1
我应该说我不是英语,所以对于单词问题感到抱歉! 我想显示的标签后在我的模板系统,这个单独工作完美:如何在我的模板系统中显示帖子标签
<?php
$text= "hi,ok,bye";
$numKeys=substr_count($text, ',');
for($i=0;$i<=$numKeys;$i++){
$exp=explode(",",$text);
$tags=$exp[$i];
echo "<a href='http://test.com/$tags'><strong>$tags</strong></a> ";
}
?>
,但是当我在我的模板系统使用它,它不工作(文章标题,时间,工作...完美的只是后标签不工作(只显示第一个标签只是一个标签,如:嗨!)):
//posts
$start = strpos($theme, '<start>');
$end = strpos($theme, '</end>', $start + strlen('</end>'));
$posty = substr($theme, $start, $end - $start);
$post = $posty;
$post = str_replace('<start>','',$post);
$post = str_replace('</end>','',$post);
$post_query = mysql_query("SELECT * FROM `posts` WHERE `bid`='{$bid}' ORDER BY `id` DESC");
$posts = '';
if($post_query) {
while($post_data = mysql_fetch_array($post_query)) {
$postid = $post_data['id'];
$post_temp = $post;
$post_temp = str_replace('[post_title]', $post_data['title'], $post_temp);
$post_temp = str_replace('[post_content]', $post_data['content'], $post_temp);
$post_temp = str_replace('[post_date]',$post_data['date'], $post_temp);
$post_temp = str_replace('[post_author]',$post_data['author'],$post_temp);
$post_temp = str_replace('[post_comments]',$post_data['comments'],$post_temp);
$post_temp = str_replace('[post_full_content]','',$post_temp);
$text= "hi,ok,bye";
$numKeys=substr_count($text, ',');
for($i=0;$i<=$numKeys;$i++){
$exp=explode(",",$text);
$tags=$exp[$i];
$post_temp = str_replace('[post_tag]',$tags,$post_temp);
}
$posts .= $post_temp;
}
}
$theme = str_replace($post, $posts, $theme);
你是什么意思'不工作?它会给你一个错误?它显示不正确吗? – 2013-04-06 21:13:06
我的意思是它只显示第一个标签!只有一个标签:嗨 – user1968224 2013-04-07 10:50:35