字符串日期转换在Javascript中无法正常工作

Question

我需要使用JavaScript以这种格式获取时间差异：“HH：MM：SS”。

我已经试过这样：

var diff = Date.parse(time2) - Date.parse(time1); 
var total_time = (diff/1000/60/60) + ":" + (diff/1000/60) + ":" + (diff/1000); 

这：

var diff = new Date(time2) - new Date(time1); 
var total_time = (diff/1000/60/60) + ":" + (diff/1000/60) + ":" + (diff/1000); 

这些时间2和时间1的值：

time1: "2012-11-07 15:20:32.161" 
time2: "2012-11-07 17:55:41.451" 

，并导致我在这两种情况下获得是：

total_time= 0.5250819444444444:31.504916666666666:1890.295 

，你可以看到的是不正确

Answer 1

你忘了删除您已经从diff计算的毫秒数。这是一个非常详细的例子，你如何以一种合适的方式来做到这一点。

var time1 = "2012-11-07 15:20:32.161", 
    time2 = "2012-11-07 17:55:41.451", 

    SECOND = 1000, 
    MINUTE = SECOND* 60, 
    HOUR = MINUTE* 60; 

var diff = new Date(time2) - new Date(time1); 

var hours = Math.floor(diff/HOUR); // Calculate how many times a full hour fits into diff 
diff = diff - (hours * HOUR); // Remove hours from difference, we already caluclated those 
var minutes = Math.floor(diff/MINUTE); // Calculate how many times a full minute fits into diff 
diff = diff - (minutes * MINUTE); // Remove minutes from difference 
var seconds = Math.floor(diff/SECOND); // As before 
diff = diff - (seconds * SECOND); 
var rest = diff; 

var total_time = hours + ":" + minutes + ":" + seconds + " " + rest ; 

DEMO

Answer 2

我认为你是因为由.划定的日期毫秒部分得到错误的DIFF值。它没有被数据解析器正确接受。

尝试使用日期和时间部分不包括如下毫秒：

var diff = Date.parse(time2.split(".")[0]) - Date.parse(time1.split(".")[0]); 

此外，当您收到错误的区别diff，你的时间计算也是错误的。

它应该是：

 var second = Math.floor(diff /1000); 
     //convert the seconds into minutes and remainder is updated seconds value 
     var minute = Math.floor(second /60); 
     second = second % 60; 

     //convert the minutes into hours and remainder is updated minutes value 
     var hour = Math.floor(minute/60); 
     minute = minute %60; 

     var total_time= hour+":" minute+":"+second;