AJV架构验证错误

Question

我有输入JSON像下面，

{"contents":[{"type":"field"},{"type":"field","itemId":"594b9980e52b5b0768afc4e8"}]} 

的条件是， 如果类型是“场”，然后“ITEMID”应该是必需字段 并且如果类型是“FIELDGROUP”或“款”，然后“ITEMID”是可选的

这是JSON模式我试着和它的工作不正常，

"type": "object", 
"additionalProperties": false, 
"properties" : { 
    "contents" : { 
     "type" : "array", 
     "items": {"$ref": "#displayItem" } 
    } 
}, 
"definitions": { 
    "displayItem" : { 
     "id": "#displayItem", 
     "type": "object", 
     "items": { 
      "anyOf": [ 
       {"$ref": "#fieldType"}, 
       {"$ref": "#fieldGroupSubSectionType"} 
      ] 
     } 
    }, 

    "fieldType" : { 

     "id": "#fieldType", 
     "type": "object", 
     "additionalProperties": false, 
     "properties": { 
      "itemId": { 
       "type": "string" 
      }, 
      "type": { 
       "type": "string", 
       "enum": ["field"] 
      } 
     } 

    }, 

    "fieldGroupSubSectionType" : { 

     "id": "#fieldGroupSubSectionType", 
     "type": "object", 
     "additionalProperties": false, 
     "properties": { 
      "itemId": { 
       "type": [ "string", "null" ] 
      }, 
      "type": { 
       "type": "string", 
       "enum": [ 
        "fieldGroup", 
        "subSection" 
       ] 
      } 
     } 

    } 
} 

任何帮助/解决方法w^ith示例Json Schema来实现上述用例，我们感激不尽。

Answer 1

如果我理解了你想要的东西的描述，那么你提供的json例子是无效的，因为它有一个类型：“field”但没有“itemId”属性。

假设这是真的。除了使用

类型的： “串”，无效]

使用需要财产。

我改变你的架构了一下，而不必单独的定义我内联它们，但除此之外，（和使用要求的）是一样的：

{ 
    "type": "object", 
    "additionalProperties": false, 
    "properties": { 
    "contents": { 
     "type": "array", 
     "items": { 
     "anyOf": [ 
      { 
      "type": "object", 
      "additionalProperties": false, 
      "properties": { 
       "itemId": { 
       "type": "string" 
       }, 
       "type": { 
       "type": "string", 
       "enum": [ 
        "field" 
       ] 
       } 
      }, 
      "required": [ 
       "itemId" 
      ] 
      }, 
      { 
      "type": "object", 
      "additionalProperties": false, 
      "properties": { 
       "itemId": { 
       "type": "string" 
       }, 
       "type": { 
       "type": "string", 
       "enum": [ 
        "fieldGroup", 
        "subSection" 
       ] 
       } 
      } 
      } 
     ] 
     } 
    } 
    } 
} 

Answer 2

下面是一些清理你的答案获得最佳做法和风格。诀窍是你需要使用暗示“暗示b < =>（不是a）或b”。在这种情况下，你有“type =字段意味着itemId是必需的< =>类型不是字段或itemId是必需的”。

{ 
    "type": "object", 
    "properties": { 
    "contents": { 
     "type": "array", 
     "items": { "$ref": "#/definitions/displayItem" } 
    } 
    }, 
    "definitions": { 
    "displayItem": { 
     "type": "object", 
     "properties": { 
     "itemId": { "type": "string" }, 
     "type": { "enum": ["field", "fieldGroup", "subSection"] } 
     }, 
     "anyOf": [ 
     { "not": { "$ref": "#/definitions/fieldType" } }, 
     { "required": ["itemId"] } 
     ] 
    }, 
    "fieldType": { 
     "properties": { 
     "type": { "enum": ["field"] } 
     } 
    } 
    } 
}