[已更新] 我是scrapy的新手,所以请和我一起裸露;我试图抓取一些数据作为我的副项目,但我收集它的问题。我一直在努力尝试两天而没有多少运气。Scrapy:使用不同的值获取来自同一网址的重复请求
第一个问题: 当我抓取帖子表单主页时,我得到一个错误的标记。
问题二: 我已阅读并试图实现
scrapy docs request得到的电话号码,却徒劳无功, 或这个答案
stackoverflow
第三个问题: 我怎么会去实现下一页(在gumtree.py中注释代码)。
第四个问题: 我现在能够得到的电话号码,但我得到的一再要求与不同的值相同的URL,[查看结果]
我真的很感激,如果有人可以给我一个方向。 我的主要目标是抓取有电话号码的帖子 我试图搜索stackoverflow,但找不到合适的帖子。 非常感谢
setting.py
BOT_NAME = 'crawler'
SPIDER_MODULES = ['crawler.spiders']
NEWSPIDER_MODULE = 'crawler.spiders'enter code here
USER_AGENT = "Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.93 Safari/537.36"
TELNETCONSOLE_ENABLED = False
gumtree.py [增订]
# -*- coding: utf-8 -*-
import re
import json
import scrapy
from scrapy import Request, Item, Field, Selector
def complete_link(string):
return string
class MyItem(Item):
token = Field()
post_id = Field()
post_url = Field()
phone_num = Field()
phone_url = Field()
class GumtreeSpider(scrapy.Spider):
name = "gumtree"
allowed_domains = ["gumtree.com"]
start_urls = [
'https://www.gumtree.com/search?search_category=cars',
]
def parse(self, response):
item = MyItem()
for href in response.css('a.listing-link::attr(href)').extract():
domain = 'https://www.gumtree.com' + href
request = Request(domain, callback=self.parse_post, meta={'domain':domain,'item':item})
yield request
# next_page = response.css('li.pagination-next a::attr("href")').extract_first()
# if next_page is not None:
# next_page = response.urljoin(next_page)
# yield Request(next_page, callback=self.parse)
def parse_post(self, response):
item = response.meta['item']
item['post_url'] = response.meta['domain']
post_id = re.match('.*?([0-9]+)$', item['post_url'])
if post_id:
item['post_id'] = post_id.group(1)
token = response.xpath('//script[contains(., "revealSellerTelephoneNumberToken")]').extract()
arr_token = re.findall(r'"([^"]*)"', str(token))
if len(arr_token) == 15:
item['token'] = arr_token[-2]
request = Request('https://www.gumtree.com/ajax/account/seller/reveal/number/' + item['post_id'], headers={'X-GUMTREE-TOKEN':item['token']}, callback=self.parse_phone, meta={'item':item})
yield request
def parse_phone(self, response):
item = response.meta['item']
phone = json.loads(response.body_as_unicode())
item['phone_num'] = phone['data']
return item
结果:[scrapy爬加姆特里-o .. \ result.json]
{"post_url": "https://www.gumtree.com/p/ford/ford-galaxy-2.0-tdci-auto-titanium-7-seater-full-service-history-alloys/1214586540", "post_id": "1214586540", "token": "eyJhbGciOiJIUzI1NiJ9.eyJuYmYiOjE0ODYyMjgwMTUsImlzcyI6Imh0dHBzOlwvXC93d3cuZ3VtdHJlZS5jb20iLCJleHAiOjE0ODYyNDk2MTQsImlhdCI6MTQ4NjIyODAxNCwiYWR2ZXJ0X2lkIjoxMjE0NTg2NTQwfQ.Lv0aCIKHo_2DbTcIw7RvE535PFAD5OX16_SFMDz--Cs", "phone_num": "004407488470949"},
{"post_url": "https://www.gumtree.com/p/ford/ford-galaxy-2.0-tdci-auto-titanium-7-seater-full-service-history-alloys/1214586540", "post_id": "1214586540", "token": "eyJhbGciOiJIUzI1NiJ9.eyJuYmYiOjE0ODYyMjgwMTUsImlzcyI6Imh0dHBzOlwvXC93d3cuZ3VtdHJlZS5jb20iLCJleHAiOjE0ODYyNDk2MTQsImlhdCI6MTQ4NjIyODAxNCwiYWR2ZXJ0X2lkIjoxMjE0NTg2NTQwfQ.Lv0aCIKHo_2DbTcIw7RvE535PFAD5OX16_SFMDz--Cs", "phone_num": "004407488470949"},
{"post_url": "https://www.gumtree.com/p/ford/ford-galaxy-2.0-tdci-auto-titanium-7-seater-full-service-history-alloys/1214586540", "post_id": "1214586540", "token": "eyJhbGciOiJIUzI1NiJ9.eyJuYmYiOjE0ODYyMjgwMTUsImlzcyI6Imh0dHBzOlwvXC93d3cuZ3VtdHJlZS5jb20iLCJleHAiOjE0ODYyNDk2MTQsImlhdCI6MTQ4NjIyODAxNCwiYWR2ZXJ0X2lkIjoxMjE0NTg2NTQwfQ.Lv0aCIKHo_2DbTcIw7RvE535PFAD5OX16_SFMDz--Cs", "phone_num": "01527853397"},
你好andjelx,感谢你的回放,但是我能够修复令牌部分,这就是为什么它有一个“直通”(第一个问题)。 – ombra23
它有什么?请给我一个例子 – andjelx
基本上我需要: “我现在能够获得电话号码,但我得到不同值的同一网址的重复请求。” 正如您从主线程中的结果可以看到的,我向同一个网址获得了三个请求,但使用了不同的电话号码。我不明白为什么。非常感谢 – ombra23