2013-03-09 36 views
0

我相信我做错了。这是我第一次尝试将碎片用于任何事情。我有一个非常简单的应用程序。我的标签中没有任何东西显示。Android的片段不显示任何东西

我相信这是一个愚蠢的错误。有人有主意吗?

这里的web.xml:

接下来,这里是从主要活动的代码应该显示这个网页流量: 公共类MainActivity扩展FragmentActivity实现ActionBar.TabListener {

SectionsPagerAdapter mSectionsPagerAdapter; 

ViewPager mViewPager; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    mSectionsPagerAdapter = new SectionsPagerAdapter(getSupportFragmentManager()); 

    // Set up the action bar. 
    final ActionBar actionBar = getActionBar(); 
    actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS); 

    // Set up the ViewPager with the sections adapter. 
    mViewPager = (ViewPager) findViewById(R.id.pager); 
    mViewPager.setAdapter(mSectionsPagerAdapter); 

    mViewPager.setOnPageChangeListener(new ViewPager.SimpleOnPageChangeListener() { 
     @Override 
     public void onPageSelected(int position) { 
      actionBar.setSelectedNavigationItem(position); 
     } 
    }); 

    for (int i = 0; i < mSectionsPagerAdapter.getCount(); i++) { 
     actionBar.addTab(
       actionBar.newTab() 
         .setText(mSectionsPagerAdapter.getPageTitle(i)) 
         .setTabListener(this)); 
    } 
} 

@Override 
public boolean onCreateOptionsMenu(Menu menu) { 
    getMenuInflater().inflate(R.menu.activity_main, menu); 
    return true; 
} 

public void onTabUnselected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) { 
} 

public void onTabSelected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) { 
    // When the given tab is selected, switch to the corresponding page in the ViewPager. 
    mViewPager.setCurrentItem(tab.getPosition()); 
} 

public void onTabReselected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) { 
} 

public class SectionsPagerAdapter extends FragmentPagerAdapter { 

    public SectionsPagerAdapter(FragmentManager fm) { 
     super(fm); 
    } 

    @Override 
    public Fragment getItem(int i) { 
     Fragment fragment = new WebViewFragment(); 
     Bundle args = new Bundle(); 
     fragment.setArguments(args); 
     return fragment; 
    } 

    @Override 
    public int getCount() { 
     return 4; 
    } 
} 

public static class WebViewFragment extends Fragment { 

    @Override 
    public View onCreateView(LayoutInflater inflater, ViewGroup container, 
      Bundle savedInstanceState) { 
     View mainView = (View) inflater.inflate(R.layout.web, container, false); 
     WebView webView = (WebView) mainView.findViewById(R.id.webview); 
     webView.loadUrl("http://www.google.com"); 


     return mainView; 
    } 
} 

}

回答

0

这很尴尬。显然,如果您忘记为因特网指定权限,那么WebView并没有太多的功能。我希望当您提出您没有权限的请求时,Android会发生错误。我在这里看了3个小时,然后张贴在这里。应该再等10分钟!