我有我的查询,我想要做什么,但我想扩大这一点,并从stockpicks表抓住所有其他informatino。它现在的功能是匹配用户搜索股票代码,然后查询我的数据库以查看是否匹配,但不允许使用该表中的其他数据。这是我有变化之前:选择所有,并作为MYSQL查询
$sqlCommand = "(SELECT id, symbol as sym FROM stockpicks WHERE symbol LIKE '%$get_quote%')";
这是我一直在试图做的和我的问题。正如我以前说过,我想简单地调用所有信息的情况下,它是需要的,而不是仅仅呼吁符号
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'as sym WHERE symbol LIKE '%hig%')' at line 1
:
$sqlCommand = "(SELECT * FROM stockpicks symbol as sym WHERE symbol LIKE '%$get_quote%')";
我得到这个错误。我不想将其他信息与搜索进行匹配,但我希望能够将其他数据与匹配结合使用来输出。如果这没有道理让我知道。感谢您提供的所有有用信息。它的无价之宝。 克里斯
编辑:表结构
ID |符号|入口|退出| openclosed |入口日期
为了更好地理解,我将包含整个脚本。我试图让变量可用,如果它是一个开放的位置。
<?php
error_reporting(E_ALL^E_NOTICE); //this is for debugging, remove if you dont need anymore
ini_set("display_errors", 1); //this is for debugging, remove if you dont need anymore
$searchoutput = "";
$ticker = "goog";
if (isset($_POST['get_quote'])) {
$ticker = $_POST['ticker'];
}
$open = fopen("http://quote.yahoo.com/d/quotes.csv?s=$ticker&f=sl1d1t1c1ohgv&e=.csv", "r");
$quote = fread($open, 1000);
fclose($open);
$quote = str_replace("\"", "", $quote);
$quote = explode(",", $quote);
$quote_0 = ($quote[0]);
$quote_1 = ($quote[1]);
$quote_2 = ($quote[2]);
$quote_3 = ($quote[3]);
$quote_4 = ($quote[4]);
$quote_5 = ($quote[5]);
$quote_6 = ($quote[6]);
$quote_7 = ($quote[7]);
$quote_8 = ($quote[8]);
echo "<div class='symbol'><div class='quote'>Company: $quote_0</div></div>";
echo "<div class='leftofStocks'><div class='row'><div class='quote'>Last trade: $$quote_1</div>";
echo "<div class='quote'>Date: $quote_2</div>";
echo "<div class='quote'>Time: $quote_3</div>";
echo "<div class='quote'>From Previous: $$quote_4</div></div>";
echo "<div class='row'><div class='quote'>Open: $$quote_5</div>";
echo "<div class='quote'>High: $$quote_6</div>";
echo "<div class='quote'>Low: $$quote_7</div>";
echo "<div class='quote'>Volume: $quote_8</div></div>";
if (isset($_POST['get_quote']) && $_POST['get_quote'] != "") {
$ticker = $_POST['ticker'];
$get_quote = preg_replace('#[^a-z 0-9?!]#i', '', $_POST['ticker']);
$sqlCommand = "(SELECT id, symbol as sym FROM stockpicks WHERE symbol LIKE '%$get_quote%')";
$sym = strtoupper($sym);
$get_quote = strtoupper($get_quote);
include_once("storescripts/connect_to_mysql.php");
$query = mysql_query($sqlCommand) or die(mysql_error());
$count = mysql_num_rows($query);
if($count >= 1){
$search_output .= "
<div class='rightOfStocks'><hr />It Looks like <strong>'$get_quote'</strong> is one of our stock picks<hr />
</div>";
while($row = mysql_fetch_array($query)){
$id = $row["id"];
$sym = $row["sym"];
$sym = strtoupper($sym);
$search_output .= "
<div class='rightOfStocks'><h3>Our Pick</h3>$sym<br />
<br />$$quote_1
</div>";
} // close while
} else {
$search_output = "
<div class='rightOfStocks'><hr />0 results for <strong>$get_quote</strong>
<hr /></div>";
}
}
?>
<div class="form"> <form method="post" action="<?php echo $_SERVER['REQUEST_URI'];?>">
Get Quote: <input type="text" size="10" maxlength="10" name="ticker"/>
<input type="submit" value="Get Quote" name="get_quote" />
Enter any valid stock quote (ie. AAPL HOG RIMM):<br></form></div>
<!--left of stock results close--></div><!--left of stock results close-->
<?php echo $search_output ;?>
</div>
SELECT * FROM stockpicks ** symbol as sym ** WHERE,粗体部分是问题之一。你也必须读一些关于sql注入的内容。 – 2013-07-03 18:17:52
你能展示你的表格结构吗?它看起来像是试图从两个表中获取信息,要做到这一点,你必须定义链接两个表之间相关记录的列 - 换句话说,就是'JOIN'条件。 –