我有这个代码的PHP部分:上查询命令的致命错误
$indice_man = $html->find('div.man', 0);
foreach($indice_man->find('div.block_results') as $e_trial_man) {
foreach($e_trial_man->find('tr.line_results') as $result_man) {
$div_medal_man = $result_man->getElementByTagName('div');
$medal_man = explode(' ',$div_medal_man->getAttribute('class'));
$Trial = trim($e_trial_man->childNodes(0)->plaintext);
$Medal = $medal_man[1];
$Sex = male;
$Name = trim($result_man->find('td.name',0)->plaintext);
$Country = trim($result_man->find('td.country',0)->plaintext);
$sql = "INSERT INTO OlympicMedal (Olimpiade, Sport, Disciplina, Medaglia, Categoria, Atleta, Nazione) VALUES ('$Game', '$Sport', '$Trial','$Medal', '$Sex', '$Name','$Country')";
}
}
我得到的错误:
Fatal error: Call to a member function getAttribute() on a non object [...]
,但如果我插入SQL前加上echo $Medal
命令,它正确打印所以我不认为getAttribute是问题。 我认为这是关于查询,我错在哪里?
法比奥
打印$ medal_man值工作,并检查或检查查询一次 – RaMeSh
检查'$ div_medal_man',它是否有'getAttribute'功能或不 – Nehal