无法登录到所需的位置

可能重复：
Undefined index: username in C:\wamp\www\Website\storeadmin\admin_login.php..and the same for password 无法登录到所需的位置

//admin_login.php 
<?php 
session_start(); 
if(isset($_SESSION["member"])){ 
    header("location:index.php"); 
    exit(); 
} 

?> 
<?php 
if(isset($_POST["username"]) && isset($_POST["password"])){  // <- Check the user has clicked the button 
    $manager = preg_replace('#[A-Za-z0-9]#i',"",$_POST["username"]); 
    $password = preg_replace('#[A-Za-z0-9]#i',"",$_POST["password"]); 



include "../storescripts/connect_to_mysql.php"; 
$sql = mysql_query("SELECT * FROM admin WHERE username ='$manager' AND password ='$password'LIMIT 1"); 
$exist_count = mysql_num_rows($sql); 
if($exist_count == 1){ 
    while(mysql_fetch_array($sql)){ 
     $id = $row["id"]; 
     } 

    $_SESSION["id"]= $id; 
    $_SESSION["manager"]= $manager; 
    $_SESSION["password"]= $password; 
    header("location:index.php"); 
    exit(); 

    } 
    else{ 
    echo 'This information is incorrect,try again <a href = "index.php">Click Here</a>'; 
    exit(); 
    } 
} 




?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
<title> AdminLogin</title> 
<link rel="stylesheet" href="../style/style.css" type="text/css" media="screen"/> 
</head> 

<body> 
<div id="mainWrapper" > 
    <?php include_once("../template_header.php");?> 
    <div id="pageContent" > 
    <div align="left" "style="margin-left:040px;"><h1>Please login to continue</h1><br /> 
    </div> 
    <form id="form1" name="form1" method="post" action="admin_login.php"> 
    UserName<br /> 
    <input type="text" name="username" id="username" size="40"/> 
    Password<br /> 
    <input type="password" name="password" id="password" size="40"/> 
    <br /> 
    <br /> 
    <br /> 
    <input type="submit" name="button" id="button" value="LogIn"/> 
    </form> 
    </div> 
    <?php include_once("../template_header.php");?> 
</div> 
</body> 
</html> 
//index.php 
<?php 
session_start(); 
if(!isset($_SESSION["member"])){ 
    header("location:admin_login.php"); 
    exit(); 
} 

$managerID = preg_replace('#[^0-9]#i',"",$_SESSION["id"]); 
$manager = preg_replace('#[A-Za-z0-9]#i',"",$_SESSION["manager"]); 
$password = preg_replace('#[A-Za-z0-9]#i',"",$_SESSION["password"]); 


include "../storescripts/connect_to_mysql.php"; 
$sql = mysql_query("SELECT * FROM admin WHERE id ='managerID' AND username ='$manager' AND password ='$password'LIMIT 1"); 
$exist_count = mysql_num_rows($sql); 
if($exist_count == 0){ 
    echo("Your login session data in not in the database"); 
    exit(); 
} 



?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<html > 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
<title>Service Admin Area</title> 
<link rel="stylesheet" href="../style/style.css" type="text/css" media="screen"/> 
</head> 

<body> 
<div id="mainWrapper" > 
    <?php include_once("../template_header.php");?> 
    <div id="pageContent" > 
    <div align="left" "style="margin-left:040px;"><h1>Hello Store Manager .What would you loke to do today</h1><br /> 
    <h3><a href="inventory_list.php">Manage Inventory</a></h3><br/><h3><a href="">Manage Me</a></h3><br/></div></div> 
    <?php include_once("../template_header.php");?> 
</div> 
</body> 
</html>

我现在面临的问题是，我不能够登录到我index.php页甚至在我已经通过phpmyadmin设置了我的数据库中指定的正确用户名和密码后。每次我尝试登录时，它都会调用echo 'This information is incorrect,try again Click Here'，如admin_login.php中所述。我感到有点沮丧。你能帮我出去吗？

来源

2012-06-27 user1485323

请尝试发布只有相关的代码。你试过什么了？ – TJHeuvel

是你的sql甚至运行？是$密码和限制之间不需要的空间吗？ SELECT * FROM admin WHERE username ='$ manager'AND password ='$ password'LIMIT 1 –

@NicholasKing sql正在运行。在你提到的空间事件之后，问题仍然存在。 – user1485323

尝试一些调试;

在preg_replace调用之前和之后检查$ _POST ['username']和$ _POST ['password']的值。
添加“或死亡mysql_error（）”您来电的mysql_query（），看看是否运行正常
回声出$ sql中的值，这样你可以看看查询。
header（）命令不需要名称和值之间的空格吗？或之后的\ r \ n？值得仔细检查。
通常在各个阶段提供更多的产出，追踪问题应该是微不足道的。

（一旦它正在工作），请在数据库的密码字段中添加crypt（）或md5（）+ salt。

来源

2012-06-27 15:12:59 lynks

即时通讯相当肯定的preg_replace根据PHP文档http://uk.php.net/manual/en/function.preg-replace.php

你试图删除它们清空你的变量

$manager = preg_replace('#[A-Za-z0-9]#i',"",$_POST["username"]); $password = preg_replace('#[A-Za-z0-9]#i',"",$_POST["password"]);

？

来源

2012-06-27 15:27:34

无法登录到所需的位置

回答

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