的JavaScript数组排序2个性能

Question

我有对象的JSON数组，看起来是这样的：

var garments [{ 
    name: 'Garment 1', 
    isDesignable: false, 
    priority: 3 
},{ 
    name: 'Garment 2', 
    isDesignable: false, 
    priority: 1 
},{ 
    name: 'Garment 3', 
    isDesignable: true, 
    priority: 3 
},{ 
    name: 'Garment 4', 
    isDesignable: true, 
    priority: 2 
},{ 
    name: 'Garment 5', 
    isDesignable: true, 
    priority: 4 
}]; 

起初，我需要通过优先，所以我这样做是为了对数组进行排序：

garments.sort(function (a, b) { 

    // By priority 
    return a.priority - b.priority; 
}); 

这很好。但现在，我意识到如果服装不是可设计的，那么它应该位于阵列的底部，而不管它是否优先。任何人都可以帮助我使用排序功能，因此所有非设计的服装都处于最底层吗？

Answer 1

使用一行代码的解决方案。

首先建立isDesignable之间的差异，如果相同，则应用差异priority作为排序指标。

var garments = [{ 
 
     name: 'Garment 1', 
 
     isDesignable: false, 
 
     priority: 3 
 
    }, { 
 
     name: 'Garment 2', 
 
     isDesignable: false, 
 
     priority: 1 
 
    }, { 
 
     name: 'Garment 3', 
 
     isDesignable: true, 
 
     priority: 3 
 
    }, { 
 
     name: 'Garment 4', 
 
     isDesignable: true, 
 
     priority: 2 
 
    }, { 
 
     name: 'Garment 5', 
 
     isDesignable: true, 
 
     priority: 4 
 
    }]; 
 
// sort isDesignable first and then by priority ascending 
 
garments.sort(function (a, b) { 
 
    return b.isDesignable - a.isDesignable || a.priority - b.priority; 
 
}); 
 
document.write('<pre>' + JSON.stringify(garments, 0, 4) + '</pre>'); 
 

 
// sort reversing the former sort order by sorting, not reversing 
 
garments.sort(function (a, b) { 
 
    return a.isDesignable - b.isDesignable || b.priority - a.priority; 
 
}); 
 
document.write('<pre>' + JSON.stringify(garments, 0, 4) + '</pre>');

Answer 2

garments.sort(function (a, b) { 
    if (a.isDesignable == b.isDesignable) { 
     return a.priority - b.priority; 
    } else if (a.isDesignable) { 
     return -1; 
    } else { 
     return 1; 
    } 
});