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我的老师希望我在玩家的选择中放置一个“嵌套验证循环”,这样可以保持循环,直到他们输入有效的输入(1,2或3)。我无法获得任何工作,我可以得到一些指示,请和谢谢。C++嵌套验证循环
#include <iostream>
#include <ctime>
#include <string>
using namespace std;
// Keaton Graffis 12/28/2015
int main()
{
int seed = time(0);
srand(seed);
char playAgain;
int playerChoice, aiChoice, win = 0, tie = 0, lose = 0;
do
{
cout << "Lets play a game of rock paper scissors.\n";
cout << "Enter a 1 for sccisors a 2 for rock or a 3 for paper: ";
// Generates outcomes of the players choice
cin >> playerChoice;
if (playerChoice == 1)
{
cout << "You picked Rock!\n";
}
else if (playerChoice == 2)
{
cout << "You picked Paper!\n";
}
else if (playerChoice == 3)
{
cout << "You picked Scissors!\n";
}
// gentrate the computers choices
int aiChoice = rand() % 3 + 1;
if (aiChoice == 1)
{
cout << "The computer chose Rock!\n";
}
else if (aiChoice == 2)
{
cout << "The computer chose Paper!\n";
}
else if (aiChoice == 3)
{
cout << "The computer chose Scissors!\n";
}
// Determines wins, ties and loses
if (playerChoice == 1 && aiChoice == 1) {
cout << "Rock meets Rock its a tie!" << endl;
tie++;
}
else if (playerChoice == 1 && aiChoice == 2)
{
cout << "Rock is covered by Paper the computer wins!." << endl;
lose++;
}
else if (playerChoice == 1 && aiChoice == 3)
{
cout << "Rock crushes Scissors you win!" << endl;
win++;
}
else if (playerChoice == 2 && aiChoice == 1)
{
cout << "Paper covers Rock you win!" << endl;
win++;
}
else if (playerChoice == 2 && aiChoice == 2)
{
cout << "Paper meets Paper its a tie!" << endl;
tie++;
}
else if (playerChoice == 2 && aiChoice == 3)
{
cout << "Paper is cut by Scissors the computer wins!" << endl;
lose++;
}
else if (playerChoice == 3 && aiChoice == 1)
{
cout << "Scissors are crushed by Rock computer wins!" << endl;
lose++;
}
else if (playerChoice == 3 && aiChoice == 2)
{
cout << "Scissors cuts Paper you win!" << endl;
win++;
}
else if (playerChoice == 3 && aiChoice == 3)
{
cout << "Scissors meet Scissors its a tie!" << endl;
tie++;
}
// Outputs wins, ties and loses
cout << "Wins: " << win << endl;
cout << "Ties:" << tie << endl;
cout << "Losses:" << lose << endl;
cout << "Would you like to play again? Y/N" << endl;
cin >> playAgain;
system("CLS");
// Allow user to play again
} while (playAgain == 'Y' || playAgain == 'y');
}
当'playerChoice'不是'1','2'或'3'时会发生什么?如果你没有'else'语句来处理这种情况? –
这就是我想要做的,但他说要使用一个循环,只是不断重复cout语句“为剪刀输入1 ...”,并不断从这里查看if/else语句。 – frodo12311
@ frodo12311查看下面的答案。 – ChrisD