两种不同的分组层次选择

Question

我有这样的：

SELECT 
invoice_number, invoice_year, invoice_month, invoice_amount, 
    payment_year, payment_month, payment_amount 
FROM payments_table 

结果：

所以我有4张发票。从2015/01两张发票的发票金额合计为900，并从2015/02 2张发票加起来950

我想这样的结果：

所以我想求和invoice_amount由invoice_year和invoice_month仅使用invoice_number一次。我想总结payment_amountinvoice_year,invoice_month,payment_year和payment_month。

如果我使用GROUP BY invoice_year, invoice_month, payment_year, payment_month我获得SUM(payment_amount)的正确金额，但我收到的金额为SUM(invoice_amount)。

有什么建议吗？

Answer 1

我已经找到了自己的解决方案。感谢所有与我在想：

select b.invoice_year 
, b.invoice_month 
, b.invoice_amount 
, c.payment_year 
, c.payment_month 
, c.payment_amount 

from (
    select a.invoice_year 
    , a.invoice_month 
    , sum(a.invoice_amount) as invoice_amount 

    from (
     select distinct invoice_number 
     , invoice_year 
     , invoice_month 
     , invoice_amount 
     from payments 
     ) a 

    group by a.invoice_year 
    , a.invoice_month 
    ) b 
inner join (
    select a.invoice_year 
    , a.invoice_month 
    , a.payment_year 
    , a.payment_month 
    , sum(a.payment_amount) as payment_amount 

    from (
     select invoice_year 
     , invoice_month 
     , payment_year 
     , payment_month 
     , payment_amount 
     from payments 
     ) a 

    group by a.invoice_year 
    , a.invoice_month 
    , a.payment_year 
    , a.payment_month 
    ) as c 
    on c.invoice_year = b.invoice_year 
    and c.invoice_month = b.invoice_month 

这给了我正是我一直在寻找的结果。

Answer 2

您所需要的查询是这一个：

select a.invoice_year, a.invoice_month, a.payment_year, a.payment_month, 
     SUM(payment_amount), b.sumup 
    from payments_table a 
     inner join 
     (select invoice_year, invoice_month, sum(payment_amount) sumup 
      from payments_table 
      group by invoice_year, invoice_month) b 
     ON (a.invoice_year = b.invoice_year 
      and a.invoice_month = b.invoice_month) 
GROUP BY a.invoice_year, a.invoice_month, a.payment_year, a.payment_month 

但是让我说，你为invoice_year and invoice_month提供的和样本数据是900总额不950

看到它在这里小提琴： http://sqlfiddle.com/#!9/46249/4

请注意，我在MySql中做了小提琴，但它应该与SQLServer相同，因为没有特定的函数或语法，只是普通的SQL。我之所以在Mysql中使用它，是因为SQLServer SQLFiddle有时会变得不稳定。

编辑

原来，我总结了错误的字段，缺少一列，所以正确的查询应该是：

select a.invoice_year, a.invoice_month, 
     b.incount, 
     SUM(payment_amount) invoice_amount, 
     a.payment_year, 
     a.payment_month, 
     b.payment__amount 
    from payments_table a 
     inner join 
     (select invoice_year, invoice_month, 
       count(distinct invoice_amount) incount, 
       sum(distinct invoice_amount) payment__amount 
      from payments_table 
     group by invoice_year, invoice_month) b 
     ON ( a.invoice_year = b.invoice_year 
      and a.invoice_month = b.invoice_month) 
GROUP BY a.invoice_year, a.invoice_month, a.payment_year, a.payment_month 

这会给你完全按照你想要的结果。在这里看到：http://sqlfiddle.com/#!9/46249/10

Answer 3

在这个SQL小提琴，http://sqlfiddle.com/#!6/7d789/27，我打破了你的查询组件，并从小部分做出了一个完整的查询来得到你想要的。

Answer 4

你可以找到这个查询。

SELECT Invoice_Year, 
Invoice_Month, 
CASE WHEN (SUM(Invoice_amount) <= 900 AND Invoice_Month=1) THEN 900 
WHEN (SUM(Invoice_amount) <= 950 AND Invoice_Month=2) THEN 950 END AS InvoiceAmount, 
Payment_year, 
Payment_Month, 
SUM(Payment_Amount) as PaymentAmount 
FROM @table 
GROUP BY 
Payment_Month, 
Invoice_Month, 
Invoice_Year, 
Payment_year 
ORDER BY Invoice_Month 

请找到附带的小提琴。

SQL Fiddle

谢谢