需要数组格式帮助吗？

Question

我有两个数组。现在我想比较两个数组中的一些元素，我需要将一个数组元素填充到新数组中。

Array1: $days this is an array of elements between two dates. 

$days = Array 
     (
     [0] => 2012-06-23 
     [1] => 2012-06-24 
     [2] => 2012-06-25 
     [3] => 2012-06-26 
     [4] => 2012-06-27 
     [5] => 2012-06-28 
     [6] => 2012-06-29 
     [7] => 2012-06-30 
     [8] => 2012-07-01 
     [9] => 2012-07-02 
     [10] => 2012-07-03 
     [11] => 2012-07-04 
     [12] => 2012-07-05 
     [13] => 2012-07-06 
     [14] => 2012-07-07 
     [15] => 2012-07-08 
     [16] => 2012-07-09 
     [17] => 2012-07-10 
     [18] => 2012-07-11 
     [19] => 2012-07-12 
     [20] => 2012-07-13 
     [21] => 2012-07-14 
     [22] => 2012-07-15 
     [23] => 2012-07-16 
     ) 

Array2: $summary is the array which i am getting from the database.. 

$summary = Array 
(
    [0] => Array 
    (
     [date] => 2012-06-23 
     [no_of_posts] => 1 
    ) 

    [1] => Array 
    (
     [date] => 2012-06-24 
     [no_of_posts] => 2 
    ) 

    [2] => Array 
    (
     [date] => 2012-06-25 
     [no_of_posts] => 1 
    ) 

    [3] => Array 
    (
     [date] => 2012-06-26 
     [no_of_posts] => 1 
    ) 

    [4] => Array 
    (
     [date] => 2012-06-27 
     [no_of_posts] => 1 
    ) 

现在这些都是数组我需要一个数组，它告诉我，在这个日子过很多次职位是有，如果有对一个日期没有职位就应该是那个为零。我试过这样.....

$result = array(); 
    foreach($summary as $key=>$s) { 
     foreach($days as $d) { 
      if($s['date'] == $d) { 
       $result[$d] = $s['no_of_posts']; 
      } else { 
       $result[$d] = 0; 
      } 
     } 
    } 

我知道有错误，我找不到...........任何想法。

输出数组需要寻找像下面.....

$result = Array 
      Array 
     (
     [2012-06-23] = 1 
     [2012-06-24] = 2 
     [2012-06-25] = 1 
     [2012-06-26] = 1 
     [2012-06-27] = 1 
     [2012-06-28] = 0 
     [2012-06-29] = 0 
     [2012-06-30] = 0 
     [2012-07-01] = 0 
     [2012-07-02] = 0 
     [2012-07-03] = 0 
     [2012-07-04] = 0 
     [2012-07-05] = 0 
     [2012-07-06] = 0 
     [2012-07-07] = 0 
     [2012-07-08] = 0 
     [2012-07-09] = 0 
     [2012-07-10] = 0 
     [2012-07-11] = 0 
     [2012-07-12] = 0 
     [2012-07-13] = 0 
     [2012-07-14] = 0 
     [2012-07-15] = 0 
     [2012-07-16] = 0 
     ) 

Answer 1

的最快方法是遍历数据库结果，并创建一个值数组按日期索引：

$summaryTotals = array(); 
foreach($summary as $dbSummary) { 
    $summaryTotals[$dbSummary['date']] = $dbSummary['no_of_posts']; 
} 

然后遍历您的日期数组，输入汇总数组中匹配的值，如下所示：

$dayValues = array(); 
foreach($days as $day) { 
    if(isset($summaryTotals[$day])) { 
     $dayValues[$day] = $summaryTotals[$day]; 
    } else { 
     $dayValues[$day] = 0; 
    } 
} 

dayValues数组现在应该是您所追求的。我相信。

Answer 2

尝试这种方式：

$newArr = array(); 

    foreach($summary as $key=>$s) { 
     $newArr[$s['date']] = $s['no_of_posts']; 
    } 

    $newDays = array_fill_keys(array_values($days),'0'); 

    $newData = $newDays + $newArr; 

    print_r ($newData); 

Answer 3

的代码应该是： $天=阵列 （ 0 => '2012-06-23'， 1 => '2012-06-24' ， 2 =>'2012-06-25'， 3 =>'2012-06-26'， 4 =>'2012-06-27'， 5 =>'2012-06-28'， 6 =>'2012-06-29'， 7 =>'2012-06-30'， 8 =>'2012-07-01'， 9 =>'2012-07-02'， 10 =>'2012-07-03'， 11 =>'2012-07-04'， 12 =>'2012-07-05'， 13 =>'2012-07-06'， 14 >'2012-07-07'， 15 =>'2012-07-08'， 16 =>'2012-07-09'， 17 =>'2012-07-10'， 18 =>' '2012-07-11'， 19 =>'2012-07-12'， 20 =>'2012-07-13'， 21 =>'2012-07-14'， 22 =>'2012 -07-15'， 23 =>'2012-07-16'， ）; $摘要=阵列 （ 0 =>数组 （ '日期'=> '2012-06-23'， 'no_of_posts'=> 1 ）

 1 => array 
     (
      'date' => '2012-06-24' , 
      'no_of_posts' => 2 
      ), 

     2 => array 
     (
      'date' => '2012-06-25', 
      'no_of_posts' => 1 
      ), 

     3 => array 
     (
      'date' => '2012-06-26' , 
      'no_of_posts' => 1 
      ), 

     4 => array 
     (
      'date' => '2012-06-27', 
      'no_of_posts' => 1 
      ) 
     ); 

    $result = array(); 
    foreach($summary as $key=>$s) { 
     foreach($days as $d) { 
      if($s['date'] == $d) { 
       $result[$d] = $s['no_of_posts']; 
      } else if(!isset($result[$d])){ 
       $result[$d] = 0; 
      } 
     } 
    }