成功消息只显示，如果只有一行被插入

Question

当我只插入一行到数据库，它显示成功消息，但如果我插入多行到数据库，然后它不显示成功消息？

下面是代码：

$studentid = (isset($_POST['addtextarea'])) ? $_POST['addtextarea'] : array(); 
$sessionid = (isset($_POST['Idcurrent'])) ? $_POST['Idcurrent'] : array(); 

$insertsql = " 
INSERT INTO Student_Session 
(SessionId, StudentId) 
VALUES 
(?, ?) 
"; 
if (!$insert = $mysqli->prepare($insertsql)) { 
// Handle errors with prepare operation here 
}          

foreach($studentid as $id) 
{ 
$insert->bind_param("ii", $sessionid, $id); 

$insert->execute(); 

if ($insert->errno) { 
echo json_encode(array('errorflag'=>true,'msg'=>"An error has occured, Students have not been added into the Assessment")); 
}else{ 
echo json_encode(array('errorflag'=>false,'msg'=>"Students have been successfully added into the Assessment")); 
} 
} 


$insert->close(); 



     ?> 

Answer 1

您需要在每次查询后不输出所有查询后移动状态消息。故障检测也是错误的。

$studentid = (isset($_POST['addtextarea'])) ? $_POST['addtextarea'] : array(); 
$sessionid = (isset($_POST['Idcurrent'])) ? $_POST['Idcurrent'] : array(); 

$insertsql = " 
INSERT INTO Student_Session 
(SessionId, StudentId) 
VALUES 
(?, ?) 
"; 

if (!$insert = $mysqli->prepare($insertsql)) 
{ 
    // Handle errors with prepare operation here 
}  

$success = true; 

foreach($studentid as $id) 
{ 
    $insert->bind_param("ii", $sessionid, $id); 

    if($insert->execute() === false) 
    { 
     $success = false; 
    } 
} 

$insert->close(); 

if($success) 
{ 
    echo json_encode(array('errorflag'=>false,'msg'=>"Students have been successfully added into the Assessment")); 
} 
else 
{ 
    echo json_encode(array('errorflag'=>true,'msg'=>"An error has occured, Students have not been added into the Assessment")); 
} 

Answer 2

你绝对确保你得到没有输出？ （我假设没有输出，因为你没有提到你得到的是错误信息）

这似乎更有可能是因为你试图输出几个json格式的字符串，无论是在另一端接受它们由于不能正确识别而导致问题的部分。将所有消息推入循环外部定义的数组可能会更好，然后在循环完成后仅响应一次。如果多余的特定查询在其余成功时失败，它也会为您提供更详细的信息。