1
我需要一些帮助来启动一个将通过数组解析的函数,检查某些值,如果这些值存在,则使用这些值创建一个新数组,然后array_push它们全部一起。解析一个巨大的mulltidimensional数组并从中构建一个新数组
我穿过阵列如此:
Array
(
[0] => Array
(
[id] => 86
[34] => 695
[39] => 0
[40.1] => Yes
[36.1] => Yes
[35.4] => Card
[33.3] => Dekalb
[33.4] => Illinois
[33.5] => 60115
[33.6] => United States
[35.1] => 1143
[33.1] => 5555 Write Rd
[33.2] => Write School
[32.6] => John
[32.3] => Smith
[28] => [email protected]
[27] => 5555556554
[25] => NIUSN
[14.3] => Jane
[14.6] => Doe
[11.2] => 695
[12] => 1
[11.1] => In-Person
[3] => 0
[2.2] => 595
[2.1] => Online
)
[1] => Array
(
...same stuff as before
)
我犯了一个函数parseArray
到我通过上述阵列。我通过每个键/值组合,如果某个键存在,我将其设置为一个变量。然后,如果存在的所有合适的变数,我联想是一个数组,然后把它推到一个最终的阵列(其中所有的值将举行):
function parseArray($arry) {
$results = array();
$current_result = array();
foreach($arry as $a) {
foreach($a as $k => $v) {
if ($k == '14.3') {
$attendee_first_name = $v;
}
if ($k == '14.6') {
$attendee_last_name = $v;
}
if ($attendee_first_name && $attendee_last_name) {
$full_name = $attendee_first_name . ' ' . $attendee_last_name;
}
}
$current_result['attendee_name'] = $full_name;
}
array_push($results, $current_result);
return $results;
}
现在他们这样,我已经做了,已经非常程序而且非常笨重。我很想了解如何为遍历数组和分配值生成更清晰/漂亮的代码。
理想我很想得到这样的事情:
Array
(
[0] => Array
(
[attendees_name] = John Smith
[attendees_email] = [email protected]
[purchasing_name] = Jane Doe
...etc
所以我可以通过一个foreach和输出简单的传递输出所需的信息很容易。
我觉得像这样的笨蛋的时候。非常感谢 ;) – tr3online