我如何将我的对象在applicationContext.xml中转换为java注释

我正在开发一个spring mvc项目，并且想要转换我在我的applicationContext.xml中创建的jpa配置， MVC 3，现在我想移动到的Spring MVC 4，写都只是使用Java注解我的JPA配置谁能帮我我如何将我的对象在applicationContext.xml中转换为java注释

这是我的applicationContext文件：

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:tx="http://www.springframework.org/schema/tx" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd 
     http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd"> 


<bean id="datasource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> 
    <property name="driverClassName" value="com.mysql.jdbc.Driver"></property> 
    <property name="url" value="jdbc:mysql://localhost:3306/db_adpub"></property> 
    <property name="username" value="root"></property> 
    <property name="password" value=""></property> 
    </bean> 

<bean id="persistenceUnitManager" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager"> 
<property name="persistenceXmlLocations"> 
<list> 
    <value>classpath*:META-INF/persistence.xml</value> 
    </list> 
</property> 
<property name="defaultDataSource" ref="datasource"></property> 
</bean> 

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> 
    <property name="persistenceUnitManager" ref="persistenceUnitManager"></property> 
    <property name="persistenceUnitName" value="adpub"></property> 
</bean> 

<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> 
    <property name="entityManagerFactory" ref="entityManagerFactory"></property> 
</bean> 

<tx:annotation-driven transaction-manager="transactionManager" /> 
<context:annotation-config></context:annotation-config> 
<mvc:annotation-driven /> 
</beans>

的Merci D'AVANCE

来源

2016-11-14 Errabi Ayoub

您将不得不按如下方式创建spring bean组件（或beans）：

@Compnonent 
MyTransactionManager 
{ 
@Autowired 
EntityManagerFactory entityManagerFactory; 

...Constructor to set properties and entityManagerFactory 
...Getters and setters 

} 

@Component 
entityManagerFactory{ 
persistenceUnitName 

@Autowired 
PersistenceUnitManager persistenceUnitManager 

...Constructor to set properties and persistenceUnitManager 
...Getters and setters 
} 

@Component 
persistenceUnitManager{ 
Values as described in properties file, for example like 

public @Value("${version}") String version; 

...Constructor to set properties 
...Getters and setters 

}

来源

2016-11-14 11:25:55 KayV

您的XML conf中的类属性ig必须在您的应用程序上下文中作为具体bean。 Java的配置synax如下（在@Configuration类）：

@Bean 
public JpaTransactionManager transactionManager() { 
    JpaTransactionManager transactionManager = new JpaTransactionManager(); 
    transactionManager.setEntityManagerFactory(entityManagerFactory()); 
    return transactionManager; 
} 

@Bean LocalContainerEntityManagerFactoryBean entityManagerFactory() { 
.... 
}

说明：您正在创建的XML配置将豆可配置与setter方法的注射（在<property> - 元素对于setter注入。因此。你必须在你的Java配置文件中创建一个bean，并用等价的setter方法设置其他bean，然后将其返回。Spring会扫描你的@Configuration类，看到上下文中应该有bean，创建它们并将它们放入应用程序上下文中

来源

2016-11-14 11:10:38 smsnheck

我如何将我的对象在applicationContext.xml中转换为java注释

回答

相关问题