StateListDrawable与编程创建的LayerDrawable不能在Android 4.0+上工作

Question

我想创建一个带彩色正方形的选项组，供用户选择一个。它正在开发一种3.2设备上，并且在这张图片看起来像：

的代码是一样的东西：

for (int i = 0; i < COLORS.length; i++) { 
     CheckBox box = new CheckBox(context); 
     box.setBackgroundDrawable(getColorOption(context, COLORS[i])); 
     box.setButtonDrawable(android.R.color.transparent); 

，然后在getColorOption功能我创建StateListDrawable：

StateListDrawable slDrawable = new StateListDrawable(); 

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] { 
      new SelectFrameShapeDrawable(transparentColor, lightRedColor), 
      new SquareShapeDrawable(color) }); 
    LayerDrawable uncheckedDrawable = new LayerDrawable(new Drawable[] { 
        new SelectFrameShapeDrawable(transparentColor, transparentColor), 
        new SquareShapeDrawable(color) }); 
    slDrawable.addState(new int[] { android.R.attr.state_checked }, 
      checkedDrawable); 
    slDrawable.addState(new int[] { -android.R.attr.state_checked }, uncheckedDrawable); 
    return slDrawable; 

SquareShapeDrawable类是ShapeDrawable类：

public class SquareShapeDrawable extends ShapeDrawable { 
    private final Paint fillpaint; 

    public SquareShapeDrawable(int color) { 
     super(new RectShape()); 
     fillpaint = new Paint(this.getPaint()); 
     fillpaint.setColor(color); 
    } 

    @Override 
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) { 
     shape.draw(canvas, fillpaint); 
    } 
} 

而且SelectFrameShapeDrawable是：

private class SelectFrameShapeDrawable extends ShapeDrawable { 
private final Paint fillpaint, strokepaint; 

public SelectFrameShapeDrawable(int fill, int stroke) { 
     super(new RectShape()); 
     strokepaint = new Paint(this.getPaint()); 
     strokepaint.setStyle(Paint.Style.STROKE); 

     strokepaint.setStrokeWidth((int) (getResources() 
       .getDisplayMetrics().density + 0.5f)); 
     strokepaint.setColor(stroke); 
     int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f); 
     setPadding(padding, padding, padding, padding); 

     fillpaint = new Paint(strokepaint); 
     fillpaint.setColor(fill); 
    } 

    @Override 
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) { 
     if (strokepaint != null) 
      shape.draw(canvas, strokepaint); 
     shape.draw(canvas, fillpaint); 
    } 
} 

在4.2设备上的所有方块是黑色的，检查时不改变：

这个问题似乎加入可绘制到StateListDrawable时.. 任何想法如何解决这个问题？

Answer 1

我解决了黑色方块问题，通过移除扩展ShapeDrawable的自定义类，并用直接使用ShapeDrawable类的代码段取代它们。此代码似乎适用于所有平台。

虽然原始问题出现在4.2而不是3.2上，但这很奇怪。我原来的灵感来源是这样的：http://www.betaful.com/2012/01/programmatic-shapes-in-android/

ShapeDrawable selectFrame = new ShapeDrawable(); 
    selectFrame.setShape(new RectShape()); 
    selectFrame.getPaint().setColor(lightRedColor); 
    selectFrame.getPaint().setStyle(Paint.Style.STROKE); 
    selectFrame.getPaint().setStrokeWidth((int) (getResources().getDisplayMetrics().density + 0.5f)); 
    int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f); 
    selectFrame.setPadding(padding, padding, padding, padding); 

    ShapeDrawable square = new ShapeDrawable(); 
    square.setShape(new RectShape()); 
    square.getPaint().setColor(color); 

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] { 
      selectFrame, square }); 
... 

Answer 2

在我的模拟器与android 4.2修订版2（最新更新），复选框不会出现，我发现问题是：当setButtonDrawable为null或ColorDrawable时，复选框度量它的大小为0的宽度。这不是StateListDrawable的原因。

我尝试设置复选框的宽度和高度，并且一切似乎都正常。 试试这个：box.setWidth（30）; box.setHeight（30）; 或者当您使用layoutparams（例如“new RelativeLayout.LayoutParams（50，50））;”将复选框添加到布局时。 希望这个帮助