进数

Question

我在SQL Server 2005中下表（不GeoCodeNum列，这是我想要计算）

+-----------+---------+-------------+----------+------------+------------+ 
| City | Region | Street | Name | Surname | GeoCodeNum | 
+-----------+---------+-------------+----------+------------+------------+ 
| Sydney | NSW  | Wall street | Chris | Red  |   1 | 
| Sydney | NSW  | Wall street | Marc  | White  |   2 | 
| Sydney | NSW  | Sea street | Joseph | Orange  |   1 | 
| Melbourne | VIC  | Ocean orad | Jess  | Brown  |   1 | 
| Florence | Tuscany | Wine street | Luca  | Rossi  |   1 | 
| Florence | Tuscany | Wine street | Mario | Verdi  |   2 | 
| Florence | Tuscany | Wine street | Luigi | Carli  |   3 | 
| Florence | Tuscany | Beer street | Elena | Sarzetto |   1 | 
| Venice | Veneto | Old street | Giovanni | Casagrande |   1 | 
| Venice | Veneto | New street | Giuseppe | Giusti  |   1 | 
+-----------+---------+-------------+----------+------------+------------+ 

我想基于以下规则GeoCodeNum ： “将一个累进数字分配给同一组城市，地区和街道的记录”。顺序号的顺序无关紧要。

在Luca Rossi，Mario Verdi和Luigi Carli都住在佛罗伦萨葡萄酒街的例子中，他们有三种不同的GeoCode数字。 Giovanni Casagande和Giuseppe Giusti都住在威尼斯，但在不同的街道上，所以他们有相同的GeoCode编号。

如何自动生成GeoCodeNum？

我需要每年生成一次结果，但我有近100000条记录。

我不知道如何开始，我试过用MS Excel，但它没有帮助。

Answer 1

select *, 
     row_number() over(partition by City, Region, Street order by Name, Surname) as GeoCodeNum 
from yourTable; 

ROW_NUMBER（）在SQL Server 2005中首次出现了： Row_Number() function in SQL Server 2005

Answer 2

我觉得这个结果你期待

;With cte(City ,Region, Street,Name ,Surname ) 
AS 
(
SELECT 'Sydney' , 'NSW'  , 'Wall street' , 'Chris' , 'Red'  UNION ALL 
SELECT 'Sydney' , 'NSW'  , 'Wall street' , 'Marc'  , 'White'  UNION ALL 
SELECT 'Sydney' , 'NSW'  , 'Sea street' , 'Joseph' , 'Orange' UNION ALL 
SELECT 'Melbourne' , 'VIC'  , 'Ocean orad' , 'Jess'  , 'Brown'  UNION ALL 
SELECT 'Florence' , 'Tuscany' , 'Wine street' , 'Luca'  , 'Rossi'  UNION ALL 
SELECT 'Florence' , 'Tuscany' , 'Wine street' , 'Mario' , 'Verdi'  UNION ALL 
SELECT 'Florence' , 'Tuscany' , 'Wine street' , 'Luigi' , 'Carli'  UNION ALL 
SELECT 'Florence' , 'Tuscany' , 'Beer street' , 'Elena' , 'Sarzetto' UNION ALL 
SELECT 'Venice' , 'Veneto' , 'Old street' , 'Giovanni' , 'Casagrande'UNION ALL 
SELECT 'Venice' , 'Veneto' , 'New street' , 'Giuseppe' , 'Giusti' 
) 
SELECT 
    City, 
    Region, 
    Street, 
    Name, 
    Surname, 
    ROW_NUMBER() OVER (PARTITION BY City, Region, Street ORDER BY Street) AS GeoCodeNum 
FROM cte 

Answer 3

SELECT city, 
     region, 
     street, 
     NAME, 
     surname, 
     Row_number() 
     OVER ( 
      partition BY city, region, street 
      ORDER BY NAME ASC) AS GeoCodeNum 
FROM customeraddress;