我希望在那里有人成功完成一个动作的7/10几率,比如爬墙。我不能让一个整数集与random.randint工作,所以我不得不重新输入10次,这样的:如何缩短此Python代码?
import random
print('You try to climb the wall.')
climbResult = random.randint(1,10)
elif climbResult == (1):
print('You were successful.')
elif climbResult == (2):
print('You were successful.')
elif climbResult == (3):
print('You were successful.')
elif climbResult == (4):
print('You were successful.')
elif climbResult == (5):
print('You were successful.')
elif climbResult == (6):
print('You were successful.')
elif climbResult == (7):
print('You were successful.')
elif climbResult == (8):
print('You were unsuccessful.')
elif climbResult == (9):
print('You were unsuccessful.')
elif climbResult == (10):
print('You were unsuccessful.')
这是一个痛苦中的数字遍地增加,这只有10部分。我只想让两个if语句,其中一个有70%的机会打印您的成功,另一个有30%的打印机会,您不成功。
对不起,这是一个非常简单的问题,我问的方式可能很难理解。我只学了两个星期的Python,而且用英语问我很麻烦,因为它不是我的第一语言。
这是在一分钟内大量upvotes的。做得很好! – mgilson
这是完美的,真的很快,非常感谢你! – user2453436
我想这就是它的方式 - 在没有记录的第三方Django包中找到一个复杂的答案,什么都不是。基本的算术比较,这里是upvotes。 –