2017-07-13 100 views
1

我使用SQL Server 2005中我有以下几点:转换逗号分隔字符串转换成XML序列号为2005

DECLARE @list NVARCHAR(MAX) 
DECLARE @xml XML 

SET @list = 'aa,bb,cc,dd,ee' 

我想从与@list数据填写@xml格式如下:

<row seq="1" col1="aa" /> 
<row seq="2" col1="bb" /> 
<row seq="3" col1="cc" /> 
<row seq="4" col1="dd" /> 

我试图@list转换成XML字符串如下:

SET @xml = '<row>' + REPLACE(@list, ',', '</row><row>') + '</row>' 

一第二则试图寻找在可以添加序列号为行@ xml.query方法FLWOR表达式,但我的运气为有SQL Server 2005中没有让条款。任何人都可以给我一个提示/解决方法吗?谢谢。

回答

0

下面是一个使用分裂功能的方式......

DECLARE @list NVARCHAR(MAX) 
DECLARE @xml XML 

SET @list = 'aa,bb,cc,dd,ee' 

;with cteSplit as(
    select * from dbo.DelimitedSplit8K(@list,',')), 

cteFinal as(
select 
    '<row seq="' + cast(ItemNumber as varchar(64)) + '" col1="' + Item + '" />' as Item 
from cteSplit) 

select Item from cteFinal --for XML AUTO 

Here is the function这已被证明是分割字符串的快速方法:

CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1)) 
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE! 

RETURNS TABLE WITH SCHEMABINDING AS 
RETURN 

/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000... 
enough to cover VARCHAR(8000)*/ 

    WITH E1(N) AS (
       SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
       SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
       SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
       ),       --10E+1 or 10 rows 
     E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows 
     E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max 
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front 
        -- for both a performance gain and prevention of accidental "overruns" 
       SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4 
       ), 
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter) 
       SELECT 1 UNION ALL 
       SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter 
       ), 
cteLen(N1,L1) AS(--==== Return start and length (for use in substring) 
       SELECT s.N1, 
         ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000) 
        FROM cteStart s 
       ) 
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found. 
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1), 
     Item  = SUBSTRING(@pString, l.N1, l.L1) 
    FROM cteLen l 
; 
GO 
+0

感谢您的回答,西蒙。在这里使用了函数ROW_NUMBER()OVER ...。我怀疑它在某些特殊情况下可能无法保留原始列表顺序,尽管其结果似乎是正确的? –

+0

它会根据你的逗号分隔字符串 – scsimon

+0

在cteTally你的元素的顺序保持秩序,我觉得应该用函数LEN(),而不是DATALENGTH(),如LEN()可以同NVARCHAR工作(X)和VARCHAR(x),并在两种情况下都给出正确的结果。以防万一我们想将参数更改为NVARCHAR(x)。 –

0

说实话,当我看着在第一次scSimon的回答中,我不喜欢它。我曾与CROSS一些不愉快的经历凑过去指数炸毁(我结束了一个十亿行的表:-))。所以,我决定用一个更全面的方法如下所示: 1.功能,以逗号分隔的列表转换成XML:

CREATE FUNCTION [dbo].[Delimited2XML](@pList NVARCHAR(MAX), @pDelimiter NCHAR(1)) 
RETURNS XML 
AS 
BEGIN 
    DECLARE @res NVARCHAR(MAX)  
    DECLARE @LEN INT 
    SET @LEN = LEN(@pList) 

    SET @res = '<root>' 

    IF (@pList IS NOT NULL AND 
     @LEN > 0 AND 
     @pDelimiter IS NOT NULL AND 
     LEN(@pDelimiter) > 0) 
    BEGIN 
     DECLARE @startIdx INT 
     DECLARE @curIdx INT 
     SET @startIdx = 1 
     SET @curIdx = 1 

     DECLARE @i INT 
     SET @i = 0 

     WHILE @curIdx > 0 
     BEGIN 
      SET @i = @i + 1; 
      SET @curIdx = CHARINDEX(@pDelimiter, @pList, @startIdx /*start_location*/) 

      IF (@curIdx > 0) 
      BEGIN 
       -- create a xml node with this format: <row seq="i" item="item_i" /> 
       SET @res = @res + ('<row Seq="' + LTRIM(STR(@i)) + '" Item="' + SUBSTRING(@pList, @startIdx /*start*/, @curIdx - @startIdx /*length*/) + '" />') 
       SET @startIdx = @curIdx + 1 
      END 
      ELSE 
      BEGIN 
       SET @res = @res + ('<row Seq="' + LTRIM(STR(@i)) + '" Item="' + SUBSTRING(@pList, @startIdx /*start*/, @LEN /*length*/) + '" />') 
      END 
     END 

    END 

    SET @res = @res + '</root>' 
    RETURN CAST(@res AS XML) 
END 
  • 功能,以XML转换为表:

    CREATE FUNCTION [DBO] [DelimitedSplit](@ pstring类型NVARCHAR(MAX),@pDelimiter NCHAR(1)) RETURNS TABLE AS RETURN WITH TDATA AS ( SELECT dbo.Delimited2XML(@ pString,@pDelimiter) AS XMLDATA ) SELECT Tab.XMLCol.value( '@序列', 'INTEGER')为SEQ, Tab.XMLCol.value( '@项目', 'NVARCHAR(MAX)')为项目 FROM TDATA CROSS APPLY XMLData.nodes( '/根/行')AS选项卡(XMLCol)

  • 我然后测试了两个函数,DelimitedSplit()和DelimitedSplit8K(),与具有1200+项的字符串。 DelimitedSplit()花了240毫秒来完成,而DelimitedSplit8K()只花了20毫秒,DelimitedSplit的仅有8%()的时间。所以,DelimitedSplit8K()具有更好的性能。

    相关问题