喜欢的东西String.Join(",", new string[] { "a", "b" });
,但Guid[]
如何将Guid []转换为String?
var guids = new Guid[] { Guid.Empty, Guid.Empty };
var str = /* Magic */
// str = 00000000-0000-0000-0000-000000000000,00000000-0000-0000-0000-000000000000
喜欢的东西String.Join(",", new string[] { "a", "b" });
,但Guid[]
如何将Guid []转换为String?
var guids = new Guid[] { Guid.Empty, Guid.Empty };
var str = /* Magic */
// str = 00000000-0000-0000-0000-000000000000,00000000-0000-0000-0000-000000000000
var str = guids.Select(g => g.ToString())
.Aggregate((working, next) => working + "," + next);
一旦你的GUID列表开始增长,拼接的这种方法将会导致性能问题。您可以修改它以使用StringBuilder:
var str = guids.Select(g => g.ToString())
.Aggregate(new StringBuilder(),
(sb, str) => sb.Append("," + str),
sb => sb.ToString());
这两者都是复杂的LINQ扩展方法。如果你的框架> = NET 3.5
String.Join(",", (from g in guids select g.ToString()).ToArray())
我认为这将工作?
StringBuilder stringBuilder = new StringBuilder();
int i = 0;
foreach (var guid in guids)
{
stringBuilder.Append(guid.ToString());
if (++i < guids.Length)
{
stringBuilder.Append(",");
}
}
var str = stringBuilder.ToString();
String.Join(",", guids.Select(g => g.ToString()).ToArray());
伟大&简单的答案 – 2010-07-26 15:22:23
.NET 4增加了一个通用的'加入'方法,你可以不加修改地传递'guids'数组 – thecoop 2010-07-26 15:32:43
@thecoop:注意,谢谢。 – 2010-07-26 15:33:52
:你也可以简单地使用的string.join。所以,在.NET 4中,只是这将工作:
String.Join(",", guids);
.NET 4中添加一个String.Join<T>(string separator, IEnumerable<T> values
方法
var str = String.Join(",", guids.Select(g => g.ToString()).ToArray());
很高兴知道,谢谢。 – BrunoLM 2010-07-26 18:52:58
String.Join(",", Array.ConvertAll(guids, g => g.ToString()));
看来这个声明无法在VS2010中通过编译? – Thomson 2010-07-26 15:48:08
Array.ConvertAll需要一个实现'Converter
//Convert string to List<string>
List<string> guidList = your_string.Split(',').ToList<string>();
//Convert string to List<Guid>
List<Guid> guidList = your_string.Split(',').ToList<string>().ConvertAll<Guid>(g => new Guid(g));
哇,完美!谢谢! – BrunoLM 2010-07-26 15:19:01
@布鲁诺,将它标记为接受的答案,如果它是为你工作的! :-) – DaveDev 2010-07-26 15:20:55
与其他方法相比,我很好奇它的工作速度。我猜Aggregate不使用String.Concat正确分配内存。 – 2010-07-26 15:23:01