删除标点符号java

Question

我试图从字符串中删除标点符号，但保留空格，因为我需要能够区分不同的单词。最终目标是找出字符串中每个单词的长度。

我设置了一个for循环来检查单词的长度，直到它遇到空格为止，但这会将标点符号计为一个字母。我知道我必须更改if语句中的变量，以反映字符串中空格的i和indexOf之间的子字符串的长度。

for(int i=0; i > stringLength - 1;){ 
original.substring(i, original.indexOf(' ')); 
if(i > minLength) 

Answer 1

虽然它可能是诱人抛出一堆维权的和IFS，这将是清洁剂只使用正则表达式：

Pattern.compile("[.,; ]+").splitAsStream(input) 

完整的例子：

import java.util.regex.Pattern; 
import java.util.stream.Collectors; 

public class Counting { 
    public static void main(String... args) { 
     String text = "This is a string. With some punctuation, but I only care about words."; 

     String wordsWithLengths = Pattern.compile("[.,; ]+") 
       .splitAsStream(text) 
       .map(word -> word + " => " + word.length()) 
       .collect(Collectors.joining("\n")); 

     System.out.println(wordsWithLengths); 
    } 
} 

输出：

This => 4 
is => 2 
a => 1 
string => 6 
With => 4 
some => 4 
punctuation => 11 
but => 3 
I => 1 
only => 4 
care => 4 
about => 5 
words => 5 

另外，如果你想算多少的话有N多角色越多，你可以：

import java.util.regex.Pattern; 

public class CountingWords { 
    public static void main(String... args) { 
     String text = "This is a string. With some punctuation, but I only care about words."; 

     int threshold = 5; 
     long amountOfWords = Pattern.compile("[.,; ]+") 
       .splitAsStream(text) 
       .filter(word -> word.length() > threshold) 
       .count(); 

     System.out.println("There are " + amountOfWords + " words with more than " + threshold + " characters"); 
    } 
} 

Answer 2

如果您只是需要得到每个字比这个会做的长度，否则，你这样做opertaion中如果statment：

int cnt = 0; 
for(int i=0; i < original.length();i++){ 
    if(",;:.?! ".indexOf(orignal.charAt(i)) > -1){ 
     if(cnt > 0){ 
      System.out.println(cnt); 
      cnt = 0; 
     } 
    } else { 
     cnt++; 
    } 
}