在另一个SO专家用户的帮助下,我实现了一种方法将viewController连接到远程PHP文件,以更新MySQL字段值并使其更新为UILabel
。JSON从PHP到iOS和从UILabel更新
我从PHP文件回显的JSON值是这种格式:[“34”]。
这是该方法:
- (IBAction)votarAction:(id)sender {
//URL definition where php file is hosted
dispatch_queue_t backgroundQueue = dispatch_queue_create("com.mycompany.myqueue", 0);
dispatch_async(backgroundQueue, ^{
int categoriaID = [[detalleDescription objectForKey:@"idEmpresa"] intValue];
NSString *string = [NSString stringWithFormat:@"%d", categoriaID];
NSLog(@"ID EMPRESA %@",string);
NSMutableString *ms = [[NSMutableString alloc] initWithString:@"http://mujercanariasigloxxi.appgestion.eu/app_php_files/cambiarvaloracionempresa.php?id="];
[ms appendString:string];
// URL request
NSLog(@"URL = %@",ms);
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:ms]];
//URL connection to the internet
NSData *responseData = [[NSURLConnection alloc]initWithRequest:request delegate:self];
NSLog(@"responseData= %@",responseData);
//Parse JSON
NSError *error = nil;
NSArray * json = [NSJSONSerialization
JSONObjectWithData:responseData
options: NSJSONReadingMutableContainers
error: &error];
int valoracionNumber = [[json objectAtIndex:0] integerValue];
dispatch_async(dispatch_get_main_queue(), ^{
//update your label
NSString *labelValue = [NSString stringWithFormat:@"%d", valoracionNumber];
self.valoracionLabel.text = labelValue;
});
});
}
这是抛出的异常:
2014-02-28 22:45:16.921 Vive Gran Canaria[928:582b] responseData= <NSURLConnection: 0xf050bc0> { request: <NSURLRequest: 0x9de3d40> { URL: http://mujercanariasigloxxi.appgestion.eu/app_php_files/cambiarvaloracionempresa.php?id=25 } }
2014-02-28 22:45:16.922 Vive Gran Canaria[928:582b] -[NSURLConnection bytes]: unrecognized selector sent to instance 0xf050bc0
2014-02-28 22:45:16.947 Vive Gran Canaria[928:582b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[NSURLConnection bytes]: unrecognized selector sent to instance 0xf050bc0'
*** First throw call stack:
(
0 CoreFoundation 0x00fca5e4 __exceptionPreprocess + 180
1 libobjc.A.dylib 0x02c5c8b6 objc_exception_throw + 44
2 CoreFoundation 0x01067903 -[NSObject(NSObject) doesNotRecognizeSelector:] + 275
3 CoreFoundation 0x00fba90b ___forwarding___ + 1019
4 CoreFoundation 0x00fba4ee _CF_forwarding_prep_0 + 14
5 Foundation 0x029a308c -[_NSJSONReader findEncodingFromData:withBOMSkipLength:] + 36
6 Foundation 0x029a323b -[_NSJSONReader parseData:options:] + 63
7 Foundation 0x029a3800 +[NSJSONSerialization JSONObjectWithData:options:error:] + 161
8 Vive Gran Canaria 0x00009bca __44-[DetalleEmpresaViewController votarAction:]_block_invoke + 602
9 libdispatch.dylib 0x02f5b7f8 _dispatch_call_block_and_release + 15
10 libdispatch.dylib 0x02f704b0 _dispatch_client_callout + 14
11 libdispatch.dylib 0x02f5e07f _dispatch_queue_drain + 452
12 libdispatch.dylib 0x02f5de7a _dispatch_queue_invoke + 128
13 libdispatch.dylib 0x02f5ee1f _dispatch_root_queue_drain + 83
14 libdispatch.dylib 0x02f5f137 _dispatch_worker_thread2 + 39
15 libsystem_c.dylib 0x03288e72 _pthread_wqthread + 441
16 libsystem_c.dylib 0x03270daa start_wqthread + 30
)
libc++abi.dylib: terminating with uncaught exception of type NSException (lldb)
这是部件从PHP文件呼应JSON数组:
$arr = array();
$rs = mysql_query("SELECT * FROM tbempresas where idEmpresa='$id'");
while ($obj = mysql_fetch_assoc($rs)) {
$arr[] = $obj['valoracionEmpresa'];
}
echo json_encode($arr);
谢谢,我认为你是对的,但是在你的代码中有一些小问题。在行[buffer appendData:data];有一个编译器警告::'data'的本地声明隐藏了实例变量。第二个问题是connectionDidFinishLoading永远不会被调用。我已经在那里放了一个NSLog,并没有出现在日志应用程序。 – mvasco
对于第一期: 你也采取了全局数据的实例名称,它的名字与委托方法类似,这就是为什么它显示警告。所以请改变全局实例变量的名称,即'webData'而不是'data ”。 并可以详细说明第二期? – Arpit
谢谢Arpit,我解决了第一个问题。第二个问题是connectionDidFinishLoading方法永远不会被调用。我已经在那里放了一个NSLog来检查它,并且在执行应用程序时不会显示它。 – mvasco