从json转换为数组

我想获取数据以在表中显示。我不知道我在做什么错，但是当我从我的页面获取数据时，它是一个单个字符的数组。我可以自己解析，但宁愿知道我做错了什么。从json转换为数组

我有这个PHP来获得数据：

function BuildViewerCombo($autocomplete) { 

    $wholeNumberCombo = array(); 
    $dbhandle = DB_Connect();  

    $result = QueryForward($dbhandle, SQL_WholeNumbersPartial($autocomplete)); 

    while($wholeNumber = sqlsrv_fetch_array($result)) 
     { 
      $wholeNumberCombo[] = array($wholeNumber['DocumentNbr'] => 'Number', $wholeNumber['DocumentRevision'] => 'Revision'); 
     } 


    //close the connection 
    sqlsrv_close($dbhandle); 

    return $wholeNumberCombo; 
}

这是从这个页面

<?PHP 
    include "Scripts/DB_Functions.php5" ; 
    include "Scripts/SQL_Viewer.php5" ; 

    $wholeNumber = $_GET['wholeNumber']; 
    echo json_encode(BuildViewerCombo($wholeNumber)); 
?>

后者从这个函数

function toggleDropdown() 
    {   

     var wholeNumberData 


     var wholeNumber = document.getElementById('WholeNumber').value; 

     if (wholeNumber != '') { 
      wholeNumberData = GetData('wholeNumber', wholeNumber); 

      var table = document.getElementById("wholeNumberDropdown"); 

      alert ('WN = ' + wholeNumberData.length); 
      alert (wholeNumberData); 
      for (var i in wholeNumberData) { 
       alert(wholeNumberData[i]); 
      } 

      } 
     else { 
      alert("Please enter a whole number."); 
     } 

    }

加载称为通过调用这个函数：

function GetData(getType, param) { 

    var http = new XMLHttpRequest(); 

    http.open("GET", 'ViewerWholeNumbers.php?wholeNumber=' + param, false); 
    http.setRequestHeader("Content-type","application/json"); 
    http.onload = function() { 
    } 
    http.send('wholeNumber=' + param); 
    return http.responseText; 
}

被返回的数据是：

[{"SS3999":"Number","A":"Revision"},{"SS3999":"Number","11":"Revision"}, 
{"SS3999":"Number","11":"Revision"},{"SS3999":"Number","11":"Revision"}, 
{"SS3999":"Number","":"Revision"},{"SS3999":"Number","11":"Revision"}, 
{"SS3999":"Number","":"Revision"},{"SS3999":"Number","11":"Revision"}, 
{"SS3999":"Number","11":"Revision"},{"SS3999":"Number","A":"Revision"}, 
{"SS3999":"Number","11":"Revision"},{"SS3999":"Number","A":"Revision"}, 
{"SS3999":"Number","11":"Revision"},{"SS3999":"Number","A":"Revision"}, 
{"SS3999":"Number","":"Revision"}]

但alert ('WN = ' + wholeNumberData.length);返回546，当我通过数组尝试循环，我得到一个字符的每一个元素，而不是值。

来源

2015-06-22 Joe

你可以使用json_decode（）函数，它是转换JSON到数组 –

是的，我同意，http://php.net/manual/en/function.json- decode.php –

返回的数据是颠倒的。它应该是{“数字”：“SS3999”...而不是其他方式 – drinovc

首先，您的关联数组被翻转。您需要更改

array($wholeNumber['DocumentNbr'] => 'Number', $wholeNumber['DocumentRevision'] => 'Revision');

到

array('Number' => $wholeNumber['DocumentNbr'], 'Revision' => $wholeNumber['DocumentRevision']);

需要，为了访问JSON的元素。然后，在您的循环中，您将使用wholeNumberData[i].Number获取编号，并使用wholeNumberData[i].Revision获取修订。

更新：

由于@jeroen指出的那样，你需要JSON.parse()到返回字符串转换成JSON。在你GetData功能与此更换你的return：

return JSON.parse(http.responseText);

来源

2015-06-22 16:57:29 imtheman

谢谢，我翻了翻。然而，当我尝试访问如下这样的成员时，我得到'undefined'：alert（'Number ='+ wholeNumberData [1] .Number）; – Joe

@Joe看看我更新的答案。 – imtheman

从json转换为数组

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