2011-11-09 79 views
1

我现在有这个解决方案随机条目:选择从MySQL与where子句

rs = lState.executeQuery("SELECT FLOOR(RAND() * COUNT(*)) 
     FROM bases 
     WHERE user_id = " + userId + " AND is_valid = 1"); 

rs.next(); 
count = rs.getInt(1); 

rs = lState.executeQuery("SELECT id, server, server_port, server_ssl, 
     server_starttls, server_auth, email, password, auth_wholemail 
     FROM bases LIMIT " + count + ", 1"); 

但它不工作,因为FLOOR(RAND() * COUNT(*))不与is_valid = 1返回ID。 那么如何从MySQL whith where子句(其中is_valid = 1)快速选择随机条目?

回答

6

尝试使用ORDER BY子句。试试这个:

SELECT COUNT(user_id) FROM bases WHERE user_id = " + userId + " AND is_valid = 1 ORDER BY RAND() LIMIT 1 

这将返回表中的一个随机行。

0

我不明白你正在尝试做的,但是这可能会帮助你(根据你的问题):

SELECT * 
FROM bases 
WHERE is_valid=1 AND user_id = <user_id> 
ORDER BY RAND() 
LIMIT 1;