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我写了一个代码并在android 4.0.3上测试;一切正常。现在我在android 4.2.2上测试它,并且填充方法不起作用。我已经简化问题,这里是一个伪代码显示了真正的问题:Android 4.2.2 Region.getBoundaryPath()图
Paint testpaint = new Paint();
testpaint.setColor(Color.BLACK);
testpaint.setAlpha(255);
testpaint.setStyle(Paint.Style.FILL);
Path p = new Path();
p.moveTo(10, 10);
p.lineTo(200, 10);
p.lineTo(200, 250);
p.lineTo(10, 200);
p.lineTo(10,10);
p.close();
RectF rectF = new RectF();
Region rr = new Region();
p.computeBounds(rectF, false);
rr.setPath(p,new Region((int) rectF.left, (int) rectF.top, (int) rectF.right, (int) rectF.bottom));
//works
RegionIterator ri = new RegionIterator(rr);
Rect rect = new Rect();
int count = 0;
while (ri.next(rect)){
canvas.drawRect(rect, testpaint);
count++;
}
//works
canvas.drawPath(p, testpaint);
//doesn't work
canvas.drawPath(rr.getBoundaryPath(), testpaint);
//works
Path outline = rr.getBoundaryPath();
Path newpath = new Path();
Matrix matrix = new Matrix();
matrix.setScale(1, 1, 0, 0);
outline.transform(matrix,newpath);
canvas.drawPath(newpath, testpaint);
第一和第二平局使得它的工作,但第三个却没有。如果我做一个零轮换,那么它也可以工作。有没有人有一个想法,为什么(我需要getBoundaryPath版本),为什么它在4.0.3上工作?据我所知,
,另一个测试: \t \t //工作 \t \t路径轮廓= rr.getBoundaryPath(); \t \t \t Path newpath = new Path(); \t \t \t Matrix matrix = new Matrix(); \t \t \t matrix.setScale(1,1,0,0); \t \t \t outline.transform(matrix,newpath); \t \t canvas.drawPath(newpath,testpaint); – user2506832