PHP：剩下几天，几小时和几分钟到某个日期？

Question

我试图让剩下的天，小时和分钟到使用php的某个日期。

但是我从我的代码很奇怪的输出，看起来像这样：

-16828 days and -11 hours and -21 minutes and -24 seconds 

未来一段时间内存储在该格式的mysql数据库：

29/01/2016 7pm 

所以我径自并做到这一点：

$Draw_time = "29/01/2016 7pm"; 

$date = $Draw_time; 
$timestamp = strtotime($date); 
$new_date = date('Y-m-d a',$timestamp); 

$seconds = strtotime($new_date) - time(); 

$days = floor($seconds/86400); 
$seconds %= 86400; 

$hours = floor($seconds/3600); 
$seconds %= 3600; 

$minutes = floor($seconds/60); 
$seconds %= 60; 


echo "$days days and $hours hours and $minutes minutes and $seconds seconds"; 

但是，当我运行此代码，我得到上述奇怪的输出！

据我所知，这可能是由于一些原因，但我能想到的唯一的事实是，我在使用我的格式a？

请问有人能就这个问题提出建议吗？

Answer 1

只需使用DateTime类等作为

$Draw_time = "29/01/2016 7pm"; 

$date = DateTime::createFromFormat("d/m/Y ha",$Draw_time); 
$date2 = new DateTime(); 

echo $diff = $date2->diff($date)->format("%a days and %H hours and %i minutes and %s seconds"); 

Answer 2

试试这个

<?php 

    $Draw_time = str_replace('/', '-', "29/01/2016 7pm"); 

    $now = new DateTime(); 

    $futureDate = new DateTime($Draw_time); 

    $interval = $futureDate->diff($now); 
    echo $interval->format("%a days %h hours %i minutes %s seconds"); 
?> 

Answer 3

试试这个。

$draw_time = "2016/01/29 7pm"; 
$date_time = explode(" ", $draw_time);// make separate date and time in array 
$date = strtotime($date_time[0]); // convert your date(2016/01/29) into php time 
$time = strtotime($date_time[1]); // convert your time(7pm) into php time 
$date = $date + $time; // make total time to count 
$new_Date = $date - (time()); // convert into difference from current time 
$day = $new_Date % 86400; 
$hrs = $new_Date % 3600; 
$min = $new_Date % 60; 
echo "Day= ".(date("d",$day)); 
echo " Hours= ".(date("h",$hrs)); 
echo " Minutes= ".(date("i",$min));