所以这里是我的代码.. 我有很多活动要切换,这段代码似乎完美。但是我想知道是否有另一种方法不像“SWITCH CASE”方法那么复杂并且易于实现。调用活动的另一种方法。
进入这里
package com.prashant.dfs;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.view.View;
import android.widget.ExpandableListView;
import android.widget.ExpandableListView.OnChildClickListener;
public class Chapter_1_full extends Activity {
ExpandableListAdapter listAdapter;
ExpandableListView expListView;
List<String> ListDataHeader;
HashMap<String,List<String>> listDataChild;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_chapter_1_full);
//get the listView(expand)
expListView = (ExpandableListView) findViewById(R.id.ch1_expand);
//prepareDataList
prepareListData();
listAdapter=new ExpandableListAdapter(this, ListDataHeader, listDataChild);
expListView.setAdapter(listAdapter);
}
private void prepareListData() {
ListDataHeader = new ArrayList<String>();
listDataChild=new HashMap<String, List<String>>();
//Adding child Data
ListDataHeader.add("1.1 Introductin to Algorithms");
ListDataHeader.add("1.2 Data Structures");
ListDataHeader.add("1.3 ADT");
List<String> Intro = new ArrayList<String>();
Intro.add("Algoithem Design ");
Intro.add("Flowcharting");
Intro.add("Pseudo-Language");
List<String> dataStructure = new ArrayList<String>();
dataStructure.add("Type of Data Structure");
dataStructure.add("Primitive and Non-Primitive");
dataStructure.add("Linear and Non-Linear");
dataStructure.add("Static and Dynamic");
List<String> ADT = new ArrayList<String>();
ADT.add("Datat Object");
listDataChild.put(ListDataHeader.get(0),Intro);
listDataChild.put(ListDataHeader.get(1),dataStructure);
listDataChild.put(ListDataHeader.get(2),ADT);
expListView.setOnChildClickListener(new OnChildClickListener() {
@Override
public boolean onChildClick(ExpandableListView parent, View v,
int groupPosition, int childPosition, long id) {
final Object childObj=parent.getExpandableListAdapter().getChild(groupPosition, childPosition);
if(childObj!=null)
{
switch (groupPosition)
{
case 0:
{
switch (childPosition)
{
case 0:
{
startActivity(new Intent(Chapter_1_full.this,TestActivity.class));
break;
}
case 1:
{
startActivity(new Intent(Chapter_1_full.this,TestActivity2.class));
break;
}
case 2:
{
startActivity(new Intent(Chapter_1_full.this,TestActivity3.class));
break;
}
}
break;
}
case 1:
startActivity(new Intent(Chapter_1_full.this,TestActivity4.class));
}
}
return true;
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.chapter_1_full, menu);
return true;
}
}
我得到这一点,只是一点点的解释会更好。 –
那么,你只需使用数组来跳过内部开关块。如果您尝试并在心理上替换“childPosition”所采用的值,您可以看到startActivity句子的等效性。 – ssantos
谢谢你,两个答案都基于相同的逻辑。现在我可以继续使用我的应用程序。再次感谢。 –