T-sql中的简单SUM

Question

这应该很简单。我正在使用SSMS 2008，试图获得只有一列的总和。问题是我目前在这一列上进行分组，并使用HAVING语句。我如何获得总记录数> 1的总和？这是我目前的T-SQL逻辑：

select count(*) as consumer_count from #consumer_initiations 
group by consumer 
having count(1) > 1 

但这个数据是这样的：

consumer_count 
---------------- 
2 
2 
4 
3 
... 

Answer 1

总结呢？

SELECT SUM(consumer_count) 
FROM (
    select count(*) as consumer_count from #consumer_initiations 
    group by consumer 
    having count(1) > 1 
) AS whatever 

Answer 2

随着嵌套查询：

select sum(consumer_count) 
FROM (

    select count(*) as consumer_count from #consumer_initiations 
    group by consumer 
    having count(1) > 1 
) as child 

Answer 3

select sum(t.consumer_count) 
    from (select count(*) as consumer_count 
       from #consumer_initiations 
       group by consumer 
       having count(1) > 1) t 

Answer 4

尝试：

select sum(t.consumer_count) from 
(
    select count(*) as consumer_count from #consumer_initiations 
    group by consumer 
    having count(1) > 1 
) t 

这会给你的纪录，你原来的查询返回的总和。这些类型的查询称为嵌套查询。

Answer 5

除了在另一个查询包裹，你可以这样做：

SELECT COUNT(*) AS consumer_count 
FROM #consumer_initiations AS a 
WHERE EXISTS 
     (SELECT * 
     FROM #consumer_initiations AS b 
     WHERE b.consumer = a.consumer 
      AND b.PK <> a.PK    -- the Primary Key of the table 
    )