1
我有一个圆滑块与客户端或网页上的滑块值。当用户更改滑块位置时,客户端必须将该值发送到服务器。在这里我使用python烧瓶作为服务器端。所以值必须从j Query或java脚本发送到瓶子。我试着用下面的代码。但是当我使用Ajax时,网页变成空白。它不显示滑块。如果我删除发送的Ajax方式,则会出现滑块,但值不会发送到服务器。如何将jQuery或JavaScript的滑块值发送到python Flask?
客户端:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>jQuery roundSlider - JS Bin</title>
<script src="https://code.jquery.com/jquery-1.11.3.js"></script>
<link rel="stylesheet" href="//cdn.jsdelivr.net/jquery.roundslider/1.0/roundslider.min.css">
<script src="//cdn.jsdelivr.net/jquery.roundslider/1.0/roundslider.min.js"></script>
</head>
<body>
<div id="slider"></div>
<div id="slide"></div>
<script>
$(document.ready(function(){
var value;
$("#slider").roundSlider({
sliderType: "min-range",
change: function(){
var obj1 = $("#slider").data("roundSlider");
value = obj1.getValue();
$("#slide").html(value);
});
$.ajax({
type: 'POST',
url: "{{url_for('test')}}",
contentType: 'application/json;charset=UTF-8',
data: {'data':value}
});
});
</script>
</body>
</html>
服务器端:
def flask():
connection()
app = Flask(__name__, template_folder='Templates')
@app.route('/test/', methods=['GET', 'POST'])
def test():
if request.method == "POST":
value=request.json['data']
print(value)
return render_template('roundslider1.html')
if __name__ == "__main__":
app.run(host='192.168.42.1',port=2030, debug=True)