您好我正在教自己android开发。首先,我已经在android上使用apache http utils实现了一个web服务器,它在模拟器上浏览localhost:8080
时提供登录页面。使用http组件解析http请求服务器端
我想知道如何解析android服务器端的登录请求。这个web服务器根据Uri请求提供内容。当提交登录页面时,表单发布到/ login。做,在localhost:8080
。
我已经注册了该动作的处理程序,如图below.I想知道如果有一种方法来解析请求主体在我的处理程序和服务html
accordingly.I只有一个字段的形式来分析,即password
。我只能读取请求标题。
在正确的方向任何意见或指针将大大appreciated.Thanks
import java.io.BufferedInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import org.apache.http.HeaderElement;
import org.apache.http.HeaderElementIterator;
import org.apache.http.HttpEntity;
import org.apache.http.HttpException;
import org.apache.http.HttpRequest;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.entity.ContentProducer;
import org.apache.http.entity.EntityTemplate;
import org.apache.http.message.BasicHeaderElementIterator;
import org.apache.http.protocol.HttpContext;
import org.apache.http.protocol.HttpRequestHandler;
import android.content.Context;
public class LoginHandler implements HttpRequestHandler {
private Context context = null;
String req;
public LoginHandler(Context context) {
this.context = context;
}
@Override
public void handle(final HttpRequest request, HttpResponse response,
HttpContext httpcontext) throws HttpException, IOException {
HttpEntity entity = new EntityTemplate(new ContentProducer() {
public void writeTo(final OutputStream outstream) throws IOException {
String resp;
OutputStreamWriter writer = new OutputStreamWriter(outstream, "UTF-8");
HeaderIterator it = request.headerIterator();
while (it.hasNext())
{
System.out.println(it.next());
}
if (validateUser()==true)
resp = "<html><head></head><body><h1>Home<h1><p>Success."+req+"</p></body></html>";
else{
resp="<html><head></head><body><h1>Home<h1><p>Login Failed.</p></body></html>";}
writer.write(resp);
writer.flush();
}
});
response.setHeader("Content-Type", "text/html");
response.setEntity(entity);
}
boolean validateUser(){
boolean valid=false;
//if valid valid=true else valid=false
return valid;
}
}
输出如下:
08-15 15:54:22.112: I/Process(650): Sending signal. PID: 650 SIG: 9
08-15 15:54:27.532: I/HTTPSERVICE(662): Creating and starting httpService
08-15 15:54:27.542: I/Notification(662): Notification Shown
08-15 16:08:19.332: I/HTTPSERVICE(662): Destroying httpService
08-15 16:08:19.352: I/Notification(662): Notification Destroyed
08-15 16:20:14.852: I/HTTPSERVICE(690): Creating and starting httpService
08-15 16:20:14.862: I/Notification(690): Notification Shown
08-15 16:20:28.102: D/dalvikvm(690): GC freed 2292 objects/135976 bytes in 157ms
08-15 16:20:28.872: I/Resources(690): Loaded time zone names for en_US in 3090ms.
08-15 16:20:28.882: I/global(690): Default buffer size used in BufferedReader constructor. It would be better to be explicit if an 8k-char buffer is required.
08-15 16:20:35.302: I/System.out(690): Host: localhost:8080
08-15 16:20:35.382: I/System.out(690): Accept-Encoding: gzip
08-15 16:20:35.422: I/System.out(690): Referer: http://localhost:8080/
08-15 16:20:35.422: I/System.out(690): Accept-Language: en-US
08-15 16:20:35.442: I/System.out(690): User-Agent: Mozilla/5.0 (Linux; U; Android 2.1-update1; en-us; sdk Build/ECLAIR) AppleWebKit/530.17 (KHTML, like Gecko) Version/4.0 Mobile Safari/530.17
08-15 16:20:35.472: I/System.out(690): Origin: http://localhost:8080
08-15 16:20:35.512: I/System.out(690): Accept: application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5
08-15 16:20:35.533: I/System.out(690): Content-Type: application/x-www-form-urlencoded
08-15 16:20:35.562: I/System.out(690): Accept-Charset: utf-8, iso-8859-1,utf-16,*;q=0.7
08-15 16:20:35.599: I/System.out(690): Content-Length: 25
我找不到任何适用的资源,我的情况下, apache site.Is可以直接从url读取requestbody?