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有没有办法跳过一个函数或构造函数中的参数。我相信有,但是每当我尝试用构造函数来做时,我都会收到一条错误消息。如何在函数中传递参数?
的Javascript
function Black(race, nation){
this.race = race ||"black";
this.nation = nation || "unknown";
}
black1 = new Black(,"America");
black2 = new Black( ,"UK");
black3 = new Black(,"S America");
console.log(black1, black2, black3);
通'undefined'或'null'。 – Pointy