2016-05-08 58 views
1

表中的行,有多个值查找具有相同价值观的PostgreSQL

id|value 
--|------ 
1 |a 
1 |b 
2 |a 
2 |b 
3 |a 
3 |c 
4 |a 
5 |a 
5 |b 
... 

所以我怎样才能选择所有的ID已作为 1相同的值的id? 我想应该是这样的

id 
-- 
1 
2 
5 

回答

2

如果你想正是相同的值,你可以使用基于集合的方法:

select t.id 
from t join 
    t t1 
    on t.value = t1.value and t1.id = 1 
group by t.id 
having count(*) = (select count(*) from t where t.id = 1); 

假设没有重复,这个计算的数量值与每个ID匹配,然后检查是否有相同的数字。

我应该承认,在string_agg()做法也是优雅:

select id 
from (select id, string_agg(value, ',' order by value) as values, 
      max(case when id = 1 then string_agg(value, ',' order by value)) over() as values_1 
     from t 
     group by id 
    ) t 
where values = values_1; 
0

还使用数组:

SELECT id 
FROM (SELECT DISTINCT id FROM t ORDER BY 1) ids 
WHERE ARRAY(SELECT value FROM t WHERE id = ids.id ORDER BY 1) = 
     ARRAY(SELECT value FROM t WHERE id = 1 ORDER BY 1); 

这应该工作,即使对于重复和/或NULL值。