运行我的java应用程序时出现gettine错误。我的应用程序捆绑在一个.jar文件中。这意味着xsd文件位于.jar文件中。在jar文件中发现类路径文件时出错
错误:错误的
class path resource [classpath*:myschema.xsd] cannot be opened because it does not exist
来源:
@Value("classpath*:myschema.xsd")
private Resource xsdFile;
public boolean validateXML()() throws IOException {
boolean isValidXMLFile = false;
Source xmlFile = new StreamSource(new File(xmlDataFile));
SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = null;
File outXsdFile = new File("autogenpath.xsd");
InputStream is =xsdFile.getInputStream();
OutputStream out=new FileOutputStream(outXsdFile);
IOUtils.copy(is, out);
try {
schema = schemaFactory.newSchema(outXsdFile);
} catch (SAXException e1) {
e1.printStackTrace();
isValidXMLFile = false;
log.debug("Error reading schema " + e1.getMessage());
}
try {
Validator validator = schema.newValidator();
validator.validate(xmlFile);
log.debug(xmlFile.getSystemId() + " is valid");
isValidXMLFile = true;
} catch (SAXParseException e) {
isValidXMLFile = false;
log.debug(xmlFile.getSystemId() + " is NOT valid");
log.debug("Reason\t\t: " + e.getLocalizedMessage());
log.debug("Line Number \t: " + e.getLineNumber());
log.debug("Column Number\t: " + e.getColumnNumber());
log.debug("Public Id\t: " + e.getPublicId());
} catch (SAXException e) {
isValidXMLFile = false;
log.debug(xmlFile.getSystemId() + " is NOT valid");
log.debug("Reason\t: " + e.getLocalizedMessage());
}
finally{
try{
out.close();
}catch(Exception e){
e.printStackTrace();
}
}
return isValidXMLFile;
}
我用的getResourceAsStream()他是为我工作。谢谢 – mahesh