Question

下面是我的代码我用于废弃一些网页 我在窗口中使用python 8

import urllib 
import re 

htmlfile = urllib.urlopen("https://finance.yahoo.com/q?s=aapl&ql=1") 
htmltext = htmlfile.read() 

regex='<span id="yfs_l84_aapl">(.+?)</span>' 

pattern = re.compile(regex) 
price = re.findall(pattern,htmltext) 
print price 

错误我得到

Traceback (most recent call last): File "C:\Python27\web.py", line 4, in htmlfile = urllib.urlopen(" https://finance.yahoo.com/q?s=aapl&ql=1 ") File "C:\Python27\lib\urllib.py", line 87, in urlopen return opener.open(url) File "C:\Python27\lib\urllib.py", line 208, in open return getattr(self, name)(url) File "C:\Python27\lib\urllib.py", line 437, in open_https h.endheaders(data) File "C:\Python27\lib\httplib.py", line 969, in endheaders self._send_output(message_body) File "C:\Python27\lib\httplib.py", line 829, in _send_output self.send(msg) File "C:\Python27\lib\httplib.py", line 791, in send self.connect() File "C:\Python27\lib\httplib.py", line 1176, in connect self.sock = ssl.wrap_socket(sock, self.key_file, self.cert_file) File "C:\Python27\lib\ssl.py", line 387, in wrap_socket ciphers=ciphers) File "C:\Python27\lib\ssl.py", line 143, in init self.do_handshake() File "C:\Python27\lib\ssl.py", line 305, in do_handshake self._sslobj.do_handshake() IOError: [Errno socket error] [Errno 1] _ssl.c:507: error:140770FC:SSL routines:SSL23_GET_SERVER_HELLO:unknown protocol

如何调试这个错误

Answer 1

使用检查元素>去安慰>检查脚本中的任何错误>管理它们>如果问题仍然存在，请转到网络选项>现在重新加载页面并检查信息流>并重新构建信息。流量停止或意外。

希望这可以解决您的问题。

Answer 2

我发现另一个答案我自己 使用inspect元素>去控制台>检查脚本中是否有错误>管理它们>如果问题仍然存在转到网络选项>现在重新加载页面并检查信息流>并重新在哪里信息。流量停止或意外。