我有onActivityResult的问题,无论我在做什么我无法得到resultCode的权利。onActivityResult - resultCode始终为0
我知道有类似的问题,但最后他们并没有帮助我,我不能修复它
MainActivity:方法,该方法将打开新的活动Popup.class
public void openShopView(){
Intent intent = new Intent(this, Popup.class);
Bundle b = new Bundle();
b.putString("which", "ShopMain");
intent.putExtras(b);
startActivityForResult(intent, 1);
}
次活动:方法,该方法将打开另一个活动Popup.class只是不同的布局
shop_c1.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Intent intent = new Intent(getIntent());
Bundle b = new Bundle();
b.putString("which", "ShopBuildings");
intent.putExtras(b);
startActivity(intent);
finish();
}
});
第三活动:和有方法,其应的setResult和靠近活性
building2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Log.i("LOG_NEW: ", "" + getCurrentBuildingTable(1) + ", " + checkSlotTable(1));
if(getCurrentBuildingTable(1) && checkSlotTable(1) == -1) {
Intent returnIntent = getIntent();
returnIntent.putExtra("result", 1);
setResult(RESULT_OK, returnIntent);
finish();
}else if (checkSlotTable(1) == -1){
Log.i("LOG_NEW: ", "Building already exist");
}
else{
Log.i("LOG_NEW: ", "Not enough resources");
}
}
});
在末端有onActivityResult()从MainActivity
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
Log.i("LOG_RES: ", "Checking.. " + requestCode + ", " + resultCode);
if (requestCode == 1) {
if(resultCode == RESULT_OK){
String result = data.getStringExtra("result");
Log.i("LOG_RES: ", result);
}
}
}
无论I” m我无法启动if(resultCode == RESULT_OK) loop和resultCode始终为0 ..
感谢您的帮助
'setResult'必须在**第二个活动叫** ,因为第二个活动的意图已在'startActivityForResult'中传递 – Saurabh
正如@Saurabh所说,结果仅从使用startActivityForResult启动的活动中接收。 –
@Saurabk 感谢您的回答,但是有什么办法可以发送第三个活动的结果,或者我应该将结果发送到第二个活动并从那里到主要活动? – fairon201