意外行为参数

Question

我有一个函数：

void sbox(uint8_t* sb1, uint8_t* sb2, uint8_t* sb3, uint8_t* sb4, uint8_t* primitive, size_t size) { 
    if(!sb1 || !sb2 || !sb3 || !sb4 || !primitive) { 
     printf("*** error: Polynomials cannot be null in sbox()\n"); 
     return; 
    } 
    uint8_t timeSb1, timeSb2, timeSb3, timeSb4; 
    timeSb1 = 62; 
    timeSb2 = 5; 
    timeSb3 = 17; 
    timeSb4 = 62; 

    sb1 = sb(sb1, sb1, sb1, size, primitive, timeSb1); 
    sb2 = sb(sb2, sb2, sb2, size, primitive, timeSb2); 
    sb3 = sb(sb3, sb3, sb3, size, primitive, timeSb3); 
    sb4 = sbr4(sb4, sb4, sb4, size, primitive, timeSb4); 
} 

其中功能SB（）和sbr4（）的第三个参数是施加在头两个参数的操作的结果，在这些函数中。其余的功能是：

uint8_t* sb(uint8_t* a, uint8_t* b, uint8_t* c, size_t size, uint8_t* primitive, size_t times) { 
    return mul2polyTimes(a, b, c, size, primitive, times); 
} 

uint8_t* mul2polyTimes(uint8_t* a, uint8_t* b, uint8_t* c, size_t size, uint8_t* primitive, size_t times) { 
if(!a || !b || !primitive) { 
    printf("*** error: Polynomials cannot be null in mul2poly()\n"); 
    return NULL; 
} 
for(int i = 0; i < times; i++) { 
    c = mul2poly(a, b, c, size, primitive); 
} 
return c; 
} 

uint8_t* mul2poly(uint8_t* a, uint8_t* b, uint8_t* c, size_t size, uint8_t* primitive)  
{ 
    if(!a || !b || !primitive) { 
     printf("*** error: Polynomials cannot be null in mul2poly()\n"); 
     return NULL; 
    } 
    uint8_t carry, prodSize; 
    uint8_t *temp; 
    carry = 0; 
    temp = NULL; 
    prodSize = 2*size; 
    c = (uint8_t*)allocate1DArray((void*)c, prodSize); 
    temp = (uint8_t*)allocate1DArray((void*)temp, prodSize); 
    for(int i = size - 1; i >= 0; i--) 
     temp[i + size] = a[i]; 
    if(b[size-1]) { 
     for(int i = size - 1; i >= 0; i--) 
      c[i + size] = a[i]; 
    } 
    for(int i = size - 2; i >= 0; i--) { 
     lShiftPoly(temp, prodSize); 
     if(b[i]) { 
      for(int ii = prodSize - 1; ii >= 0; ii--) { 
       if(carry) { 
         if(c[ii] && temp[ii]) { 
           c[ii] = 1; 
           carry = 1; 
       } else if(c[ii] || temp[ii]) { 
          c[ii] = 0; 
          carry = 1; 
          } else { 
          c[ii] = 1; 
       carry = 0; 
        } 
       } else { 
        if(c[ii] && temp[ii]) { 
           c[ii] = 0; 
         carry = 1; 
       } else if(c[ii] || temp[ii]) { 
          c[ii] = 1; 
           carry = 0; 
       } else { 
           c[ii] = 0; 
           carry = 0; 
          } 
       } 
      }    
     } 
    } 
    uint8_t reduce; 
    reduce = 0; 
     for(int i = 0; i < size; i++) { 
     if(c[i]) { 
      reduce = 1; 
      break; 
     } 
    } 

    if(reduce) { 
     for(int i = 0; i < prodSize; i++) 
      c[i] ^= primitive[i]; 
    } 
    uint8_t* d; 
     d = NULL; 
    d = (uint8_t*)allocate1DArray((void*)d, size); 
    for(int i = size; i < prodSize; i++) { 
     d[i-size] = c[i]; 
    }  
    free(c); 
    c = d; 
    return c; 
    } 

我注意到，称S盒（）之后，引用值的值保持不变，但是当函数内检查他们被相应的设置。我在这里错过了什么？

注意：这些功能需要这么多参数的原因与编程无关。

Answer 1

这条线mul2poly()：

c = (uint8_t*)allocate1DArray((void*)c, prodSize); 

不传播的mul2poly()特定调用的外部新的分配。您需要将第三个参数作为uint8_t**并将其正确解引用，以便在C中执行所需的操作。