我试图从URL中获取两个参数以添加到我的上下文中。从URL中获取参数slugs
这是网址:
url(r'^company/(?P<company>[\w\-\_]+)/?/(?P<program>[\w\-\_]+)/?$', RegistrationView.as_view(),
name='test'),
的观点:
class RegistrationView(RegistrationMixin, BaseCreateView):
form_class = AppUserIntroducerCreateForm
template_name = "registration/register_introducer.html"
slug_field = 'company'
def get_context_data(self, *args, **kwargs):
context = super(RegistrationIntroducerView, self).get_context_data(**kwargs)
print(self.get_slug_field())
context['company'] = ??????
context['program'] = ??????
return context
我想尽一切办法获取值self.company
,kwargs['company']
等等,我有什么错我在这里干什么?
self.kwargs是要走的路。一个例子是在这里:http://stackoverflow.com/questions/6629426/django-class-based-generic-views-and-authentication – mawimawi