提问生成新的观测
我想在我的数据集的变量()系统地更改为“混合”其电流值之间的中介的行。通过混合现有的观察{R}
数据
我目前有5年递增的州县和人口数据。数据在数据框中。
data:
year state county population
1 1990 Vermont Chittenden 4050
2 1995 Vermont Chittenden 4180
3 2000 Vermont Chittenden 4205
4 2005 Vermont Chittenden 4350
5 2010 Vermont Chittenden 4358
6 2015 Vermont Chittenden 4401
使用的技术在这里找到:Change variable value based on row index {R},我申请了以下内容:
new.data <- data[rep(1:nrow(data),each=5),]
new.data$year <- new.data$year + sequence(rep(5,nrow(data))) -1
其结果是,我得到这个:
new.data:
year state county population
1 1990 Vermont Chittenden 4050
1.1 1991 Vermont Chittenden 4050
1.2 1992 Vermont Chittenden 4050
1.3 1993 Vermont Chittenden 4050
1.4 1994 Vermont Chittenden 4050
2 1995 Vermont Chittenden 4180
2.1 1996 Vermont Chittenden 4180
2.2 1997 Vermont Chittenden 4180
2.3 1998 Vermont Chittenden 4180
2.4 1999 Vermont Chittenden 4180
3 2000 Vermont Chittenden 4205
...
5 2010 Vermont Chittenden 4358
5.1 2010 Vermont Chittenden 4358
5.2 2011 Vermont Chittenden 4358
5.3 2012 Vermont Chittenden 4358
5.4 2013 Vermont Chittenden 4358
6 2015 Vermont Chittenden 4401
但是,请注意没有变化一次五年。我想找出一种方法来在增量值之间“混合”中间值。它看起来是这样的:
new.data:
year state county population
1 1990 Vermont Chittenden 4050
1.1 1991 Vermont Chittenden 4076
1.2 1992 Vermont Chittenden 4102
1.3 1993 Vermont Chittenden 4128
1.4 1994 Vermont Chittenden 4154
2 1995 Vermont Chittenden 4180
2.1 1996 Vermont Chittenden 4185
2.2 1997 Vermont Chittenden 4190
2.3 1998 Vermont Chittenden 4195
2.4 1999 Vermont Chittenden 4200
3 2000 Vermont Chittenden 4205
...
5 2010 Vermont Chittenden 4358
5.1 2011 Vermont Chittenden 4367
5.2 2012 Vermont Chittenden 4376
5.3 2013 Vermont Chittenden 4385
5.4 2014 Vermont Chittenden 4394
6 2015 Vermont Chittenden 4401
我该如何做到这一点?
如果需要,我很乐意发布更多信息。谢谢!
看看'seq'函数。 –
Hi @TimothéePoisot,你想介绍一下吗?我对R还是比较陌生的。我明白'seq'允许规定'from'和'to';然而,我不知道如何每五年重复一次。谢谢! – Yasha