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我在我的PHPMYADMIN中有这些表,我想要的是使用ID获取每个团队的名称,我一直尝试使用LEFT JOIN,但它只返回1个团队,否则它会返回将返回null加入2个表ON 2字段
此匹配表
| match_id | HomeTeam | AwayTeam |
+------------------------------------------------
| 1 | 3 | 1 |
,这表队
| team_id | team_name |
+----------------------------------------
| 1 | Manchester |
| 2 | Barcelona |
| 3 | Real Madrid |
这个结果我想SQL返回
|match_id|HomeTeam|AwayTeam| Home_name | Away_name |
+-----------------------------------------------------
| 1 | 3 | 1 | Real Madrid | Manchester|
我一直在试图使用此SQL语句
SELECT `match.*`,`team_*` FROM `match`
LEFT JOIN `team` ON `match.HomeTeam` = `team.match_id`
LEFT JOIN `team` ON `match.AwayTeam` = `team.match_id`
WHERE `match.match_id` = 1
任何解决方案?
目前我使用这个PHP代码,但它的效率不高,我想
$Query = 'SELECT * FROM match WHERE match_id = 1'
// excute Query //
foreach($match_array as $match)
{
$Query = 'SELECT FROM team WHERE team_id = '.$match['HomeTeam'].''
$home_team_name = somthing
$Query = 'SELECT FROM team WHERE team_id = '.$match['AwayTeam'].''
$away_team_name = something
}
**非常感谢** – 2012-02-05 02:28:31
@OthmanAbahossain欢迎您。 – dgw 2012-02-05 03:18:06