如何将日期从DD-MM-YYYY转换为MM-DD-YYYY的字符串

Question

我一直在为此工作大约一周，并且出于某种原因，我无法克服它。我在搜索数组的元素时遇到了超出范围的错误，并尝试将需要的字符移动到需要的数组中。

无效showFileDateCleansed（字符串第[]，字符串最后[]，字符串生日[]）{

string tempHoldDD[10]; 
string tempHoldMM[10]; 
/* 
The stuff below is working so Ijust commented it out until I figure out the isssue I am having with the dates 
for (int i = 0; i < 6; i++) 
{ 
first[i].at(0) = toupper(first[i].at(0)); 
last[i].at(0) = toupper(last[i].at(0)); 
} 

for (int i = 0; i < 10; i++) 
{ 
cout << first[i] << " "; 
cout << last[i] << "\n"; 
}*/ 

int d = 0; //Im using this to keep track of whether I have passed the delimiter in the text file "-" 
bool done = false; 
for (int i = 0; i < 10; i++) 
{ 

    done = false; 
    int c = 0;//this is used for the character within the element of the array, it increments at the bottom so that it moves to the next character. 

    while (done != true) 
    { 

     // <TK> Check for invalid character 
     if (c == 0) 
     { 
      std::cout << "Invalid character at index: " << i << std::endl; 

     } 

     if (birthday[i].at(c) == '-') 
     { 
      d += 1; 
      done = true; 
     } 
     else 
     { 
      switch (d) 
      { 
      case 0: 
      { 

       // Try catch to prevent the out of range exception from crashing. 
       //try 
       //{ 
        // Debug 
        std::cout << "C: " << c << std::endl; 

        // create a temporary variable for the value. 
        char temp = birthday[i].at(c); 
        tempHoldDD[i].at(c) = temp; 
       //} 
       /*catch (std::out_of_range const& exc) 
       { 
        std::cout << exc.what() << '\n'; 
       }*/ 

       //cout << tempHoldMM[c] << "\n"; 

      } 

      case 1: 
      { 
       // Try catch to prevent the out of range exception from crashing. 
       try 
       { 
        // Debug 
        std::cout << "C: " << c << std::endl; 

        // create a temporary variable for the value. 
        char temp = tempHoldMM[i].at(c); 
        birthday[i].at(c) = temp; 
       } 
       catch (std::out_of_range const& exc) 
       { 
        std::cout << exc.what() << '\n'; 
       } 

       //cout << tempHoldMM[c] << "\n"; 
       c += 1; 
       break; 
      } 


      } 



     } 

    } 

} 

Answer 1

你case 1在switch声明没有break声明，所以它会落空到case 2，其中c递增。难道这会让c超出范围吗？