2012-12-15 110 views
0

我不是SQL专家,我很难找到解决方案来为以下情况制作SQL查询。我希望有人能帮助我这个!分组答案需要SQL查询解决方案

我有几个表的答案表持有20个问题表的答案。答案可以有1到5的值。

问题有一个types_id标记相关的问题。

我需要的是在答案表的查询,并得到了以下信息:

集团所涉及的问题(=相同types_id =相同teamid和=同一日期),并从答案拿AVG是有相同的types_id。

所以结果可能是这样的:

--------------------------------------------------------- 
|          types_id  | 
|teamid | date    | 1 | 2 | 3 | 4 | 
--------------------------------------------------------- 
| 12 | 2012-12-31 00:00:00 | 2 | 4 | 3 | 5 | <- holds the average answers from the related questions (= same types_id) 
--------------------------------------------------------- 

此处作为一例的问题1,5,9,13和17通过那里的1 types_is涉及因此,有4组的相关问题。

下表结构的一个样本:

Answers表:

----------------------------------------------------------------------------------------------------------------------------------------------------- 
id teamid userid date     Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20 timestamp   done 
----------------------------------------------------------------------------------------------------------------------------------------------------- 
1  12  1 2012-12-31 00:00:00  1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 2012-12-11 08:30:27 0 
2  12  2 2012-12-31 00:00:00  5 2 5 5 5 5 4 4 4 4 4 3 3 3 3 3 2 2 2 2 2012-12-11 08:50:08 0 
3  12  3 2012-12-31 00:00:00  1 3 1 1 1 1 2 2 2 2 2 4 4 4 4 4 5 5 5 5 2012-12-11 08:20:37 0 
1  9  11 2012-12-31 00:00:00  1 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 2012-12-11 08:30:27 0 
2  9  12 2012-12-31 00:00:00  5 2 5 5 5 5 4 4 4 4 4 3 3 3 3 3 2 2 2 2 2012-12-11 08:50:08 0 
3  9  23 2012-12-31 00:00:00  1 3 1 1 1 1 2 2 2 2 2 4 4 4 4 4 5 5 5 5 2012-12-11 08:20:37 0 
    ----------------------------------------------------------------------------------------------------------------------------------------------------- 

Questions

--------------------------------- 
id question   types_id 
--------------------------------- 
1 Question 1 text  1 
2 Question 2 text  2 
3 Question 3 text  3 
4 Question 4 text  4 
5 Question 5 text  1 
6 Question 6 text  2 
7 Question 7 text  3 
8 Question 8 text  4 
9 Question 9 text  1 
10 Question 10 text  2 
11 Question 11 text  3 
12 Question 12 text  4 
13 Question 13 text  1 
14 Question 14 text  2 
15 Question 15 text  3 
16 Question 16 text  4 
17 Question 17 text  1 
18 Question 18 text  2 
19 Question 19 text  3 
20 Question 10 text  4 
--------------------------------- 

任何帮助将不胜感激!

谢谢阿伦

+0

如果您的答案表中没有每个问题20个列,而是20个行,并且有一个question_id列,这会更容易。 – Laurence

+0

您使用的是什么RDBMS? – Taryn

+0

首先使表格正常化。 – Kermit

回答

1

首先你需要unpivot的问题数据。如果您不准备以这种方式存储数据,我会为此创建视图。你需要这个扩大到所有20个问题:

Create View UnpivotedAnswers As 
Select 
    teamid, 
    date, 
    1 as QuestionID, 
    Q1 as Answer 
From 
    Answers 
Union All 
Select 
    teamid, 
    date, 
    2 as QuestionID, 
    Q2 as Answer 
From 
    Answers 
Union All 
Select 
    teamid, 
    date, 
    5 as QuestionID, 
    Q5 as Answer 
From 
    Answers 

一旦你有这种格式提供的数据,得到平均数可以像这样做:

Select 
    u.teamid, 
    u.date, 
    avg(case When q.types_id = 1 Then Answer End) as type1, 
    avg(case When q.types_id = 2 Then Answer End) as type2, 
    avg(case When q.types_id = 3 Then Answer End) as type3, 
    avg(case When q.types_id = 4 Then Answer End) as type4, 
    avg(case When q.types_id = 5 Then Answer End) as type5 
From 
    UnpivotedAnswers u 
    Inner Join 
    Questions q 
    On u.QuestionID = q.id 
Group By 
    u.teamid, 
    u.date 

http://sqlfiddle.com/#!2/b1b718/1

+0

非常感谢你! – Aren