更改了一些名称和内容以保护我的工作。MySQL 1064没有语法错误时出现语法错误
DELIMITER //
CREATE PROCEDURE glt(IN howMany INT)
BEGIN
DECLARE f VARCHAR(32);
DECLARE done INT DEFAULT 0;
DECLARE curs CURSOR FOR SELECT DISTINCT id FROM tpd;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1;
OPEN curs;
DROP TABLE IF EXISTS lt;
CREATE TEMPORARY TABLE lt LIKE tpd;
REPEAT
FETCH curs INTO f;
IF NOT done THEN
INSERT INTO lt SELECT * FROM tpd WHERE id = f ORDER BY TIME DESC LIMIT howMany;
END IF;
UNTIL done END REPEAT;
CLOSE curs;
END
上面的代码给Linux机器上下面的错误,而不是Mac计算机,尽管两者都是大小写的文件系统,并具有相同的MySQL版本:
ERROR 1064 (42000) at line 172: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'howMany;
END IF;
UNTIL done END REPEAT;
CLOSE curs;
END' at line 16
Bye
感谢那种先生!这是一个奇怪的行为...特别是因为代码在Mac上运行mysql没有问题。只是不能在Linux上工作... –