覆盖2个不同大小的位图，合成一个大小的屏幕

Question

我有2个位图，一个是：宽度为720 x 404的高度。另一种是1280x550 我用这个功能：

public Bitmap overlay(Bitmap bmp1, Bitmap bmp2) { 
    Bitmap bmOverlay = Bitmap.createBitmap(bmp1.getWidth(), bmp1.getHeight(), bmp1.getConfig()); 
    Bitmap bmp2new = getResizedBitmap(bmp2, bmp1.getHeight(), bmp1.getWidth(), bmp2.getConfig()); 
    Canvas canvas = new Canvas(bmOverlay); 
    canvas.drawBitmap(bmp1, new Matrix(), null); 
    canvas.drawBitmap(bmp2new, 0, 0, null); 
    return bmOverlay; 
    } 

现在它让我两者。覆盖。现在第一个，是一个视频的屏幕截图，第二个是我画的画布。问题是，如果我在屏幕边缘的东西上绘制某些东西，它将被错误地覆盖（偏移），因为我的视频被拉伸为与seconc图片相同。 我能做些什么，把两个图片，但屏幕捕捉开始与一个像素的偏移量，所以它将被正确放置？

我想：

int left = (int)((bmp2.getWidth() - (bmp1.getWidth()*(bmp2.getHeight()/bmp1.getHeight())))/2.0); 
    Bitmap bmp1new = getResizedBitmap(bmp1, bmp2.getHeight(), ((bmp2.getWidth() - (bmp1.getWidth()*(bmp2.getHeight()/bmp1.getHeight())) , bmp1.getConfig()); 
    Bitmap bmptest = Bitmap.createBitmap(bmp1new, left, 0,bmp1new.getWidth() - left, bmp1new.getHeight()); 

但没有运气，现在我更糊涂了

Answer 1

它与这工作：

public Bitmap overlay(Bitmap bmp1, Bitmap bmp2) { 
    Bitmap bmOverlay = Bitmap.createBitmap(bmp2.getWidth(), bmp2.getHeight(), bmp1.getConfig()); 
    float left =(bmp2.getWidth() - (bmp1.getWidth()*((float)bmp2.getHeight()/(float)bmp1.getHeight())))/(float)2.0; 
    float bmp1newW = bmp1.getWidth()*((float)bmp2.getHeight()/(float)bmp1.getHeight()); 
    Bitmap bmp1new = getResizedBitmap(bmp1, bmp2.getHeight(), (int)bmp1newW , bmp1.getConfig()); 
    Canvas canvas = new Canvas(bmOverlay); 
    canvas.drawBitmap(bmp1new, left ,0 , null); 
    canvas.drawBitmap(bmp2, new Matrix(), null); 
    return bmOverlay; 
    }